Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Hope this helps ;)
Its 78/10 = 39/5
Hope it helps :)
Answer:
Option (1).
Step-by-step explanation:
Statement given states that "A canary's beak is, at most 20 mm long."
Word "at most" means "the maximum".
So at most length of the beak means "length of the beak is less than equal to 20 mm".
And the expression representing this statement algebraically will be,
x ≤ 20
Therefore, option (1) will be the correct option.
2/12 is the correct answer
Answer:
Step-by-step explanation:
1 3^2 is =
subtract what u get from up here
boooooom
