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3 years ago

9

I have 6 surfaces 2 of my surfaces are smaller then the others I can stand up tall what shape am I

2 answers:

Arada [10]3 years ago

5 0

This shape would be a rectangular prism, with 4 rectangular sides, and 2 square or smaller rectangular sides.

An example of a rectangular prism would be a brick. It has 4 sides that are perfectly alike, then two other sides that are like each other.

s2008m [1.1K]3 years ago

5 0

the correct answer would be This shape would be a rectangular prism, with 4 rectangular sides, and 2 square or smaller rectangular sides.

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Simplify (9^2/3*9^4/2)/9^1/2

JulsSmile [24]

Answer:

$\frac{9^{5}}{3}$

Step-by-step explanation:

$\frac{9^{2}}{3} * \frac{9^{4}}{2} = \frac{9^{6}}{6}\\\\\frac{\frac{9^{6}}{6}}{\frac{9^{1}}{2}} \\\\\frac{2*9^{6}}{6*9^{1}}\\\\\frac{9^{5}}{3}$

$\frac{9^{5}}{3} = 19,683$

6 0

3 years ago

Which interval is the solution set to 0.35x - 4.8 < 5.2 -0.9x?

8_murik_8 [283]

Answer: $(-\infty, 8)$

Step-by-step explanation:

Given the following inequality:

$0.35x - 4.8 < 5.2 -0.9x$

You need to solve for "x" in order to find the solution.

The steps are:

1. Add $0.9x$ to both sides of the inequality:

$0.35x - 4.8+0.9x < 5.2 -0.9x+0.9x\\\\1.25x-4.8$

2. Add $4.8$ to both sides:

$1.25x-4.8+4.8$

3. Divide both sides by $1.25$ :

$\frac{1.25x}{1.25}$

Notice that "x" is less than 8. This indicates that 8 is not included in the solution and you must use parentheses.

The solution in Interval notation is:

$(-\infty, 8)$

8 0

3 years ago

Read 2 more answers

Dm de math appareil photo aidee moi svp svpppp

mixer [17]

No idea what language you're talking in, sorry but I only understand English? There is no photo here either.

Please Evaluate?

Thank you.

8 0

3 years ago

The coordinates of ADEF are D(-1, 4), E (7,-3), and F (9,5). Write a rule for the translation of ADEF to ADEF. so that the centr

mr Goodwill [35]

Answer:

Step-by-step explanation:

i think the answer is x but ignore this

8 0

3 years ago

What is the product of 3y<br> product of (3y^)(274)

Dima020 [189]

3y^-4 × (2y^-4) = 6y^-8

= 6/1/y^8

= 6/y^8

.................................................

1) When x^1 multiply with x^2, 1 will add to 2 and become 3

= x^3

2) y^-1 = 1/y

3^-2 = 1/3^2 = 1/9

5^-2 = 1/5^2 = 1/25

5 0

3 years ago