![\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }](https://tex.z-dn.net/?f=%5Ctext%7B%20Jake%20father%20can%20carry%20%7D%2010%5Cfrac%7B5%7D%7B7%7D%20%5Ctext%7B%20or%20%7D%20%5Cfrac%7B75%7D%7B7%7D%20%5Ctext%7B%20pounds%20%7D)
<em><u>Solution:</u></em>
From given question,
Number of pounds Jake carry = ![6\frac{1}{4} \text{ pounds }](https://tex.z-dn.net/?f=6%5Cfrac%7B1%7D%7B4%7D%20%5Ctext%7B%20pounds%20%7D)
Number of pounds his father carry is
times as much as jake
To find: Number of pounds Jake father can carry
<em><u>Convert the mixed fractions to improper fractions</u></em>
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator
![\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}](https://tex.z-dn.net/?f=%5Crightarrow%206%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B4%20%5Ctimes%206%2B1%7D%7B4%7D%20%3D%20%5Cfrac%7B25%7D%7B4%7D%5C%5C%5C%5C%5Crightarrow%201%5Cfrac%7B5%7D%7B7%7D%20%3D%20%5Cfrac%7B7%20%5Ctimes%201%2B5%7D%7B7%7D%20%3D%20%5Cfrac%7B12%7D%7B7%7D)
<em><u>Then according to question,</u></em>
![\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}](https://tex.z-dn.net/?f=%5Ctext%7BPounds%20father%20carry%20%7D%20%3D%20%5Cfrac%7B12%7D%7B7%7D%20%5Ctext%7B%20times%20the%20pounds%20jake%20carry%20%7D%5C%5C%5C%5C%5Ctext%7BPounds%20father%20carry%20%7D%20%3D%20%5Cfrac%7B12%7D%7B7%7D%20%5Ctimes%20%5Cfrac%7B25%7D%7B4%7D%5C%5C%5C%5C%5Ctext%7BPounds%20father%20carry%20%7D%20%3D%20%5Cfrac%7B75%7D%7B7%7D%5C%5C%5C%5C%5Ctext%7BIn%20terms%20of%20mixed%20fractions%2C%20%7D%5C%5C%5C%5C%5Ctext%7BPounds%20father%20carry%20%7D%20%3D%20%5Cfrac%7B75%7D%7B7%7D%20%3D%2010%5Cfrac%7B5%7D%7B7%7D)
![\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }](https://tex.z-dn.net/?f=%5Ctext%7B%20Thus%2C%20Jake%20father%20can%20carry%20%7D%2010%5Cfrac%7B5%7D%7B7%7D%20%5Ctext%7B%20or%20%7D%20%5Cfrac%7B75%7D%7B7%7D%20%5Ctext%7B%20pounds%20%7D)
Answer:
ACBD
Step-by-step explanation:
Increases, gains, earnings, upward motion are all represented by positive numbers. Decreases, losses, spending, downward motion are all represented by negative numbers. Here are the sums:
A: -33.57 +14.98 = -18.59
B: 7 2/5 -3/5 = 7 +(2/5 -3/5) = 7 -1/5 = 6 4/5
C: 3 1/6 +2 1/2 = (3+2) +(1/6 +3/6) = 5 4/6 = 5 2/3
D: 23.66 -15.84 = 7.82
__
Least to greatest, their order is ...
A (-18.59), C (5 2/3), B (6 4/5), D (7.82)
Answer:
Step-by-step explanation:
In order to find the area of the circle base, we need the radius, and we don't have it. We'll use the volume to find the radius, as follows:
and fill in the givens:
and solve that for r;
so
r = 3.784698783 and plug that in for the radius to find the area of the circle base:
so
gives you that
A = 45 meters squared, exactly. No decimal.
ANSWER: -8x + 56
Standard Form Equation: y=mx+b
Answer:
$50.
Step-by-step explanation:
Let the full price be x dollars, then:
x - 0.20x = 40
0.80x = 40
x = 40/0.80
x = 50.