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kvasek [131]
3 years ago
10

PLEASE HURRY! 30 PTS! Which statements are true? SELECT EACH CORRECT ANSWERS! A.) 100x^3+5=5x^3(20x+1) B.)4x^2+10x=2x(2x+5) C.)3

0x^4−12x^3=6x^3(5x−2) D.)8x^3−6x=2x^3(4−3x^3)
Mathematics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

B.)4x^2+10x=2x(2x+5)

Step-by-step explanation:

kirill [66]3 years ago
4 0

Answer:

B and C

Step-by-step explanation:

Distribute

4x^2 + 10x = 4x^2 +10x

30x^4 - 12x^3 = 30x^4 - 12x^3

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nignag [31]

Answer:

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3 years ago
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
What mixed number is equal to 6/4
Norma-Jean [14]

1 and a half

............

4 0
3 years ago
Read 2 more answers
Classify the following triangle check all that apply
saw5 [17]

Answer:

c.Right

Step-by-step explanation:

because of the 90 degrees it shows that it is 90 degrees

7 0
3 years ago
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