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3 years ago

10

PLEASE HURRY! 30 PTS! Which statements are true? SELECT EACH CORRECT ANSWERS! A.) 100x^3+5=5x^3(20x+1) B.)4x^2+10x=2x(2x+5) C.)3

0x^4−12x^3=6x^3(5x−2) D.)8x^3−6x=2x^3(4−3x^3)

2 answers:

Svet_ta [14]3 years ago

7 0

Answer:

B.)4x^2+10x=2x(2x+5)

Step-by-step explanation:

kirill [66]3 years ago

4 0

Answer:

B and C

Step-by-step explanation:

Distribute

4x^2 + 10x = 4x^2 +10x

30x^4 - 12x^3 = 30x^4 - 12x^3

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1.64698101 rounded to the nearest hundred-thousandth is?

muminat

Answer:

1.64698 is the correct answer.

Step-by-step explanation:

3 0

3 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

The length of a rectangle is five times its width. If the area of the rectangle is 320 cm^2, find its perimeter.

olchik [2.2K]

A = LW
A = 320
L = 5W

320 = W(5W)
320 = 5W^2
320/5 = W^2
64 = W^2
sqrt 64 = W
8 = W

L = 5W
L = 5(8)
L = 40

so the length (L) = 40 cm and the width (W) = 8 cm

P = 2(L + W)
P = 2(40 + 8)
P = 2(48)
P = 96 <=====

4 0

3 years ago

What is a correct equation for the line passing through the point (-2,1) and having slope m=1/2

frez [133]

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We ahve the slope m = 1/2 and the point (-2, 1). Substitute:

$y-1=\dfrac{1}{2}(x-(-2))$

$y-1=\dfrac{1}{2}(x+2)$ - point-slope form

Covert to the slope-intercept form (y = mx + b):

$y-1=\dfrac{1}{2}(x+2)$ <em>use the distributive property</em>

$y-1=\dfrac{1}{2}x+1$ <em>add 1 to both sides</em>

$y=\dfrac{1}{2}x+2$ - slope-intercept form

Convert to the standard form (Ax + By = C):

$y=\dfrac{1}{2}x+2$ <em>multiply both sides by 2</em>

$2y=x+4$ <em>subtract x from both sides</em>

$-x+2y=4$ <em>change the signs</em>

$x-2y=-4$ - standard form

Convert to the general form (Ax+By+C=0):

$x-2y=-4$ <em>add 4 to both sides</em>

$x-2y+4=0$ - general form

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3 years ago

The sum of 12 and twice Chrissy's savings

Mrrafil [7]

24 should be your answer

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3 years ago