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svp [43]
3 years ago
5

If m and n are zeros of ax2-5x+c, find a and c when m+n=mn=10

Mathematics
1 answer:
kompoz [17]3 years ago
6 0
ax^2+bx+c=0
if m and n are zeros, then:
m+n=\dfrac{-b}{a}\ and\ mn=\dfrac{c}{a}
We have:
ax^2-5x+c=0\to b=-5\\\\m+n=mn=10
substitute
m+n=\dfrac{-(-5)}{a};\ mn=\dfrac{c}{a}\\\\ \left\{\begin{array}{ccc}\dfrac{5}{a}=10&\to a=\dfrac{1}{2}\\\\\dfrac{c}{a}=10\end{array}\right
substitute the value of a to the second equation:
\dfrac{c}{\frac{1}{2}}=10\\\\2c=10\ \ \ |:2\\\\c=5

Answer:  \boxed{a=\dfrac{1}{2};\ c=5}


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Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

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Find the measure of angle B

Applying the law of cosines

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2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

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step 3

Find the measure of angle C

Applying the law of cosines

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Consider her processing fee of $35 per loan processed. If she processed 900 loans, then we can say she got paid ($35 * 900) = $31500 for her processed loans that year.

Then, to find her yearly total earnings, we simply add those two values. $30000 + $31500 = $61500.

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