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3 years ago

They said brainly was the best ive had a question up sense the day before yesterday and havent even had a person see it.

1 answer:

riadik2000 [5.3K]3 years ago

4 0

Well the main reason nobody answered was because your question sucks fam,

but as far as what amount I'd say $400...i think

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Isaiah is preheating his oven before using it to bake. The initial temperature of the oven is 75° and the temperature will incre

antoniya [11.8K]

Answer:

12750 is the answer... god bless

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3 years ago

The propellers on the Titanic have a radius of 23.5 ft and weigh 38 tons each. If the propellers turn at 180 rpm, what would be

melamori03 [73]

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3 years ago

Sam and Bryan meet at the gym. Sam travels 6 miles farther to the gym than Bryan. Three times the distance Bryan travels is 12

Digiron [165]

Answer:

x+6=y and 3x=12

Step-by-step explanation:

Let x be the distance traveled by Bryan and let y be the distance traveled by Sam then the first equation would be:

x+6=y (x plus 6 is equal to y, Bryan's distance plus 6 is equal to Sam's distance) and the second one is:

3x=12 (3 times x is 12, 3 times the distance travelled by Bryan is 12)

So our statements/equations are:

x+6=y and

3x=12 (we dont write this as x=4 as it asks us to give the statements we got from the information given, we only start simplifying once it tells us to solve)

4 0

3 years ago

PLEASE HELP IVE BEEN WAITING FOR 2 HOURS

garik1379 [7]

Answer is C because it is proportion.

6 0

3 years ago

Read 2 more answers

A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0

3 years ago