Choose the equation that represents a line that passes through points (−1, 2) and (3, 1).

What is the y-coordinate of the solution for the system of equations? x−y=−11 y+7=−2x

ICE Princess25 [194]

Answer:

$y= 5$

Step-by-step explanation:

Given the system of equations:

$x-y=-11$

$y+7=-2x$

In order to find the y coordinate of the solution we must first find the solution to this system of equations. We first start by solving one of the given equations and then substitute the answer of that into the second equation and further solve to get the final answers.

$x=y=-11$

$y+7=-2x$

$+ -7$

$y = -2x - 7$

$x - y = -11$

$y = -2x-7$

$x-(-2x-7)=-11$

$x--2x=x+2x=3x$

$3x+7=-11$

$-7$

$-11+-7=-18$

$3x=-18$

$\div3$

$-18\div3=-6$

$x=-6$

$y=-2x-7$

$y=(-2)(-6)-7$

$-2\times-6=12-7=5$

$y=5$

Hope this helps.

7 0

1 year ago

Find the Slope using the Slope Formula

ExtremeBDS [4]

Answer: -1

2-1=1
1/-3+2
1/-1
=-1

7 0

3 years ago

Find the slope and y-intercept of each equation<br><br>y = x - 3<br>m = ?<br>b = ?

barxatty [35]

Answer:

m = 1

b= -3

Step-by-step explanation:

4 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

coldgirl [10]

Answer:

z = -0.4.

Step-by-step explanation:

Here's the formula for finding the z-score (a.k.a. standardized normal variable) of one measurement $x$ of a normal random variable $X \sim N(\mu,\; \sigma^{2})$ :

$\displaystyle z = \frac{x-\mu}{\sigma}$ ,

where

$z$ is the z-score of this measurement,
$x$ is the value of this measurement,
$\mu$ is the mean of the random normal variable, and
$\sigma$ is the standard deviation (the square root of variance) of the random normal variable.

Let the length of a trout in this lake be $X$ inches.

$X \sim N(30, \; 4.5^{2})$ .

$\mu = 30$ , and
$\sigma = 4.5$ .

For this measurement, $x = 28.2$ . Apply the formula to get the z-score:

$\displaystyle z = \frac{x - \mu}{\sigma} = \frac{28.2 - 30}{4.5} = -0.4$ .

5 0

2 years ago

The largest possible circle is to be cut from a 12-foot square board. Calculate the approximate area, in square feet, of the rem

olchik [2.2K]

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Find Area of the circle:
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Area of a circle = πr²
Area of the largest possible circle = π x(12 ÷ 2)²
Area of the largest possible circle = 113.10 ft²

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Find Area of the square board:
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Area of a square board = Length x Length
Area of the square board = 12 x 12
Area of the square board = 144 ft²

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Find area of the remaining board:
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Area of the remaining board = 144 - 113.10
Area of the remaining board = 30.90 ft²

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Answer: The area of the remaining board is 30.90 ft².
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5 0

2 years ago