All categories

2 years ago

Which expressions are equivalent to x² +4?

Mathematics

1 answer:

n200080 [17]2 years ago

8 0

Answer:

4x2

Step-by-step explanation:

You might be interested in

A square has an area of 144 sq. units. how long is its perimeter?

Arada [10]

Formula for Area of a square:

$\boxed {\boxed {\text {Area = Length x Length}}}$

Given that the area is 144 unit²:

$\text {Length}^2 = 144$

$\text {Length} = \sqrt{144} = 12 \text { units}$

Formula for Perimeter of a square:

$\boxed {\boxed {\text {Perimeter = 4 x Length }}}$

$\text {Perimeter = } 4 \times 12 = 48 \text { units}$

$\boxed { \boxed { \text {Answer: The perimeter is 48 units.}}}$

6 0

2 years ago

At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a

laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0

2 years ago

80% of your employees work in production.What fraction of the employees work in production?

Alex Ar [27]

0.8 of employees work in production

4 0

3 years ago

Read 2 more answers

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.