3 years ago

What is the quotient (3x4 – 4x2 + 8x – 1) ÷ (x – 2)?

1 answer:

8 0

To find the quotient of (3x^4 – 4x^2 + 8x – 1) ÷ (x – 2), First: divide 3x^4 by x to get 3x^3, then multiply 3x^3 to x - 2 to get 3x^4 - 6x^3 and subtract 3x^4 - 6x^3 from 3x^4 – 4x^2 + 8x – 1 to get 6x^3 - 4x^2 + 8x - 1 Next: divide 6x^3 by x to get 6x^2, then multiply 6x^2 to x - 2 to get 6x^3 - 12x^2 and subtract 6x^3 - 12x^2 from 6x^3 - 4x^2 + 8x - 1 to get 8x^2 + 8x - 1 Next: divide 8x^2 by x to get 8x, then multiply 8x to x - 2 to get 8x^2 - 16x and subtract 8x^2 - 16x from 8x^2 + 8x - 1 to get 24x - 1 Finally: divide 24x by x to get 24, then multiply 24 to x - 2 to get 24x - 48 and subtract 24x - 48 from 24x - 1 to get 47. Thus, <span>(3x^4 – 4x^2 + 8x – 1) ÷ (x – 2) = 3x^3 + 6x^2 + 8x + 24 Remainder 47</span>

You might be interested in

What is the answer to 6x^2+17x+12=0 pls help me and I will help you back

Rina8888 [55]

Answer:

x=−4/3 or x=−3/2

Step-by-step explanation:

Let's solve your equation step-by-step.

6x2+17x+12=0

Step 1: Factor left side of equation.

(3x+4)(2x+3)=0

Step 2: Set factors equal to 0.

3x+4=0 or 2x+3=0