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RUDIKE [14]
4 years ago
9

(a) find parametric equations for the line that passes through the point (−2, 5) and is parallel to the vector <3, −8>. (e

nter your answer as a comma-separated list of equations where x and y are in terms of the parameter t.)
Mathematics
1 answer:
Fittoniya [83]4 years ago
6 0
= <-2 +3t, 5 -8t>

Multiply the direction vector by the parameter and add it to the given point.
You might be interested in
What is the surface area of the figure shown? (use 3.14 for pi)
SpyIntel [72]

This is a combination of the formula of several figures.

The first one is the bottom of the cylinder AKA a circle.
The second one is the cylinder - the bottom and the top.
The third one is a cone without a bottom.

The first one can be written like this: r^2*3.14 where r is the radius of the circle
The second one is written like this: 2*3.14*r*h where r is the radius, and h the height
The third one is written like this: l*r*3.14

After this you just have to input the values. 
bottom        cylinder        Cone             (Use calculator if possible)
(3^2*3.14)+(2*3.14*3*5)+(6*3*3.14)=
28.26 + 94.2 + 56.52 = 178.98 in^2

The correct answer is 178.98 in^2.
Youre welcome. 




EXTRA:

If youre wondering how to find the different formulas, you can search for the full formula, then remove the parts you do not need, by matching them with the formula of the part you want to remove.

Example:
Cylinder:
SA = 2(pi<span> r</span><span> 2</span><span>) + (2 </span><span>pi </span><span>r)* h
</span>In this case, i didnt need the top and bottom, then i look for the formula of a circle.
Circle SA = pi r^2

Is this anywhere in the cylinder? Yes! The first part.
Then we are left with:
2 + (2 pi r)*h
But that 2 looks strangely placed, and with some reason, one quickly understands that it means "top AND bottom", but since we removed the circle surface, we have to remove that part too. 
So the final result of the formula is:
2 pi r h


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What integer is between 27 + 1 and 72 ?
alexira [117]

Answer:

there's kinda alot of numbers there pal

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