Always
Anytime point A is on line BC, AB+BC=BC
Answer:
c) 4
Step-by-step explanation:
<u><em>The sum of two numbers is 14. The larger number minus three times the lesser number is -2</em></u>
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To solve this question, we need to write the statement mathematically;
Let the two numbers be x and y
"The sum of two numbers is 14" can be mathematically written as x+y = 14
and
"The larger number minus three times the lesser number is -2" can be mathematically written as x - 3y = -2
x + y = 14 ------------------(1)
x - 3y= -2 -------------------(2)
Subtract equation (2) from equation (1)
[x - x = 0 y - (-3y)=4y 14-(-2)=16]
4y = 16
To get the value of y divide both-side of the equation by 4
4y/4 = 16/4
y = 4
Substitute y=4 into equation (1)
x + y =14
x +4 =14
Subtract 4 from both-side of the equation
x + 4 -4 = 10]-4
x = 10
x=10 and y =4
Therefore the lesser number is 4
Answer: TnT down
Step-by-step explanation:
What's given?
EG ≅ FG
∟EFG ≅ ∟FGH
What's something else we can figure out?
∠FGE ≅ ∠GFH - alternate interior angles
Can we prove these congruent?
We can prove this congruent by using AAS
Geez I think I'm losing my touch but I hope this is correct and it helped!
Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
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We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
2+2 is 4 LOL you just gotta add 1+1+1+1
