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Nikolay [14]
3 years ago
11

On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine

burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = -16t 2 + 64t + 80, where t is time in seconds. The maximum height of the rocket is how many feet.
Mathematics
1 answer:
Savatey [412]3 years ago
4 0
H'(x)=-32t+64, the only zero of that is 2, and it goes from positive to negative, so the maximum height will be at time 2. Plug in 2 to the original equation and that gives you 144. The max height is 144 feet.
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Step-by-step explanation:

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5 0
3 years ago
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Nataly_w [17]
There are enough information's already given in the question. Based on those information's that answer can be easily deduced.
Radius of the sphere = 8 units
Then
Surface area of the sphere = 4 *pi * r^2
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I hope that this answer has come to your help.
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3 years ago
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