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kondor19780726 [428]
2 years ago
15

Help please show work please please

Mathematics
1 answer:
patriot [66]2 years ago
3 0

Answer:

wow

Step-by-step explanation:

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Quick algebra problem, please show work!
cricket20 [7]
5/x^2-1^2 + 3/x+1
5/(x+1)(x-1) + 3/x+1
5+3(x-1)/(x+1)(x-1)
5+3x-3/(x+1)(x-1)
Final answer : 3x+2/(x+1)(x-1)
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3 years ago
Mike got in and elevator and whent down 3 floors. he meant to go to a lower level,so he stayed on the elevator and when down 3 m
Naily [24]
It is negative six because down three is -3 so 3+3 =6 but the numbers are negative so the answer is -6
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3 years ago
A teacher divided students into groups of 3. Each group of 3 wrote a report that had 9 pictures in it. The students used 585 pic
jeyben [28]
So this is what i did but im not sure if its 100% correct

585 / 9 to get the number of groups = 65

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3 years ago
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help I literally got a 4/10 in my math test and my mom is like REALLLLY mad that she took my phone so I’m using my sisters ipad
Aloiza [94]

Answer:

3/8 < 2/4

2/3 > 7/12

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2 years ago
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I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
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