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2 years ago

Dilation does not preserve congruence. True or False

Mathematics

1 answer:

Leno4ka [110]2 years ago

5 0

Answer:

True

Step-by-step explanation:

Dilation changes the size of the image so therefore it can't be congruent with the pre-image as congruent means the same.

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Jaime went to the mall with $42. If he bought a T-shirt and had $18 left, how much did the T-shirt cost Jaime in dollars?

nirvana33 [79]

Answer:

$24

Step-by-step explanation:

You simply do $42-$18

=24

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3 years ago

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nlexa [21]

Answer:

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2 years ago

Fifty-five percent of the members of the junior varsity swim team wear glasses. Of the team memebers who do not wear glasses, 30

GarryVolchara [31]

the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade is 14%.

Given, the members of the junior varsity swim team wear glasses is 55%.

And the members of junior varsity swim team who do not wear glasses and in 10th grade is 30%.

Let the total no. of members be x.

So, the members of the junior varsity swim team wear glasses (55%),will be

$0.55x$ .

The total number of members not wearing glasses, will be

$x - 0.55 x = 0.45 x$ .

Now, the no. of members not wearing glasses and in 10th grade will be,

$\frac{0.45x\times30}{100} =0.135x$

We know that the probability of an event E, P(E) will be,

$P(E)=\frac{No.\ of Favourable\ outcomes}{total \ no. \ of \ outcomes}$

So, the probability for no. of members not wearing glasses and in 10th grade will be,

$P(E)=\dfrac{0.135x}{x}$

$P(E)=0.135\\\\P(E)=13.5 \%$

Hence the nearest whole percent of probability is 14%.

For more details on probability follow the link:

brainly.com/question/795909

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2 years ago

What’s z over 5 to the 2 power

Snowcat [4.5K]

Just square the top and bottom. z^2 over 25

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3 years ago

in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume

Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

4 0

2 years ago