4/3pi *r3 = 972pi
Divide both side by pi
4/3 *r3 = 972
r3 = 972* 3/4
r3 = 729
r = the square root of 729 to the third power (I don't know if I'm expressing this correctly but answer is 9, hope you get that)
r = 9 that's your answer.
Hope it's correct, appreciate if you could let me know
Answer:
![6 \sqrt[3]{5}](https://tex.z-dn.net/?f=6%20%5Csqrt%5B3%5D%7B5%7D)
Step-by-step explanation:
For the problem, ![\sqrt[3]{24} *\sqrt[3]{45}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%2A%5Csqrt%5B3%5D%7B45%7D)
, use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.
![\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%2A%5Csqrt%5B3%5D%7B45%7D%20%3D%20%5Csqrt%5B3%5D%7B24%2A45%7D)
You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.
![\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3} = 6 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%2A45%7D%20%3D%5Csqrt%5B3%5D%7B3%2A8%2A5%2A3%2A3%7D%20%20%3D%206%20%5Csqrt%5B3%5D%7B5%7D)
Answer:
yes
Step-by-step explanation:
A math teacher opened a window company because he loves seeing shapes or geometrical polygons such as rectagles, squares or quadrilaterals in general as well as triangles in his works. Of course, the math teacher is already familiar with these shapes and how to calculate the angles in between.
