Please help with question tagged below
2 answers:
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Answer:
see below
Step-by-step explanation:
If we let X represent the number of bagels produced, and Y the number of croissants, then we want ...
(a) Max Profit = 20X +30Y
(b) Subject to ...
6X +3Y ≤ 6600 . . . . . . available flour
X + Y ≤ 1400 . . . . . . . . available yeast
2X +4Y ≤ 4800 . . . . . . available sugar
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Production of 400 bagels and 1000 croissants will produce a maximum profit of $380.
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In the attached graph, we have shaded the areas that are NOT part of the solution set. (X and Y less than 0 are also not part of the solution set, but are left unshaded.) This approach can sometimes make the solution space easier to understand, since it is white.
The vertex of the solution space that moves the profit function farthest from the origin is the one we are seeking. The point that does that is (X, Y) = (400, 1000).
Hi!
The first number line is equals to
The second number line is equals to
The third number line is equals to
The fourth number line is equals to 2
The fifth number line is equals to 0
The sixth number line is
The answer is; second, fourth and fifth number lines.
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<em>I hope, I could help.</em>
<em>Wish Good Lessons! ^-^</em>