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Bumek [7]
3 years ago
8

Alexis has 6 more collector's cards than Danny. Together, the two friends have 24

Mathematics
2 answers:
Pavel [41]3 years ago
7 0

Answer:

18

Step-by-step explanation:

notsponge [240]3 years ago
5 0

Answer:

18

Step-by-step explanation:

24-6

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Will correctly calculated 45 ÷ 6 as 7.5. How can he find 4,500 ÷ 6 without dividing?
Anastasy [175]
Add the zeros on to 7.5 to which you would move the decimal and it should be like this 750.0 or 750
5 0
3 years ago
An inverse variation includes the point (4,17). Which point would also belong in this inverse variation?
NARA [144]

Answer:

(2, 34 )

Step-by-step explanation:

Since the points vary inversely then half the x, means double the y, thus

(2, 34) or (1, 68 ) would also belong in this inverse variation

3 0
3 years ago
What is the range of h?
Bas_tet [7]

Answer:

-3 ≤y≤6

Step-by-step explanation:

The range is the output values or the y values

The y values go from -3 to 6 including these values

-3 ≤y≤6

3 0
3 years ago
There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors
zhuklara [117]
<h3>Answer: A) 1</h3>

=========================

Explanation:

Let's label each pair of outcomes as an ordered pair (x,y)

x = first spinner outcome

y = second spinner outcome

We have these 12 different possible combos

(1,3),   (1,4),   (1,5),   (1,6)

(2,3),  (2,4),  (2,5),  (2,6)

(3,3),  (3,4),   (3,5),  (3,6)

Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.

Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.

7 0
3 years ago
A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3296 tickets overall. It has s
rodikova [14]

Answer:

1022 of $10 tickets, 1326 of $20 tickets, 948 of VIP $30 tickets

Step-by-step explanation:

We can set-up a system of equations to find the number of each kind of ticket. We know there are the cheap tickets c, the medium tickets m and the VIP tickets v. Since 3296 tickets were purchased, then c+m+v=3296.

We also know that 304 more medium priced tickets have been sold then cheap tickets. We write 304+c=m.

Lastly, we know that a total of $65,180 was sold. We write 10c+20m+30v=65,180.

We will solve by substituting one equation into the other. We substitute m=304+c into c+m+v=3296. Simplify and isolate the variable v.

c+m+v=3296

c+(304+c)+v=3296

c+304+c+v=3296

2c+304-304+v=3296-304

2c-2c+v=2992-2c

v=2992-2c

We will now substitute this into the remaining equation with our first substitution.

10c+20m+30v=65,180

10c+20(304+c)+30(2992-2c)=65,180

10c+6080+20c+89760-60c=65180

-30c+95840=65180

-30c+95840-95840=65180-95840

-30c=-30660

c=1022

This means 1,022 tickets purchased were $10 tickets. We substitute this equation back into m=304+c to find m.

m=304+1022

m=1326

This means 1,326 were $20 tickets.

Lastly we know 948 VIP tickets were bought because 1022+1326+948=3296


7 0
3 years ago
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