Apply slip and slide
a^2-3a-4
(a-4)(a+1)
(a-2)(2a+1)
Find zeros
a-2=0
a=2
2a+1=0
2a=-1
a=-1/2
Final answer: {-1/2, 2}
Step-by-step explanation:
y = |x - 2| - 1
Given equation is in the form of y=|x-h|+k
Where (h,k) is the vertex
h = 2 and k =-1
So (2, -1) is the vertex for the given function
To find x intercepts we plug in 0 for y
we will get two values for x because of absolute function
0 = |x-2| -1
add 1 on both sides
|x-2| =1
x-2 =1 and x-2 =-1
x= 3 and x= 1
So x intercepts are (1,0) and (3,0)
the graph is attached below
Answer:
x=-3
Step-by-step explanation:
-x-20=4x-5
-20=5x-5
-15=5x
x=-3