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algol13
4 years ago
9

What is the y-intercept of this line?​

Mathematics
2 answers:
Pavel [41]4 years ago
5 0
Negative 6 as it passes through the axis y at -6
andreyandreev [35.5K]4 years ago
4 0
-6 Because That Were The Line Intercepts With The Y-Axis
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one a windy moring a hot air balloon starts ascending and flying away from the too of a hill the alritude h(x) in feet of the ba
makkiz [27]

The greatest common factor of all the coefficients is of 8.

<h3>What is the greatest common factor?</h3>

The greatest common factor between multiple terms is the largest value for which all terms are divisible.

In this problem, the equation is:

h(x) = -16x^2 + 56x + 96

The terms are 16, 56 and 96. Hence, to find the gcf, we have to keep factoring them by prime factors while all can be factored by the same value, hence:

16 - 56 - 96|2

8 - 28 - 48|2

4 - 14 - 24|2

1 - 7 - 12

There are no terms by which both 7 and 12 are divisible, hence the procedure is stopped and:

gcf(16, 56, 96) = 2³ = 8.

You can learn more about the greatest common factor at brainly.com/question/26140769

3 0
3 years ago
Select all expressions that equal -6-(-2)
riadik2000 [5.3K]

Answer:

-6-(-2) is equivalent to

-6 +2

and 2-6

a) and b) are correct options

4 0
3 years ago
Read 2 more answers
3. Solve the equation using square roots. If the equation has no real solution, write
noname [10]
3) x² - 121 = 0

x² = 121

x' = +√121

x' = 11

_______________

x'' = - √121

x'' = -11

Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)

4) 4x² + 144 = 0

4x² = -144

x² = -144 / 4

x² = -36

x = √-36

No solution ⇒ S = ∅

5) z²+10z+21 = 0

Δ = 10² - 4(1)(21)

Δ = 100 - 84

Δ = 16

x' = (-10+4) / 2 = -6/2 = -3

x'' = (-10-4) / 2 = -14/2 = -7

Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
4 0
3 years ago
35,892 rounded to nearest 10
Goshia [24]

Answer:

35,890

...........

8 0
3 years ago
Read 2 more answers
The quadratic function fhas a vertex at (3,4) and opens upward. The quadratic function g is shown below.
Alecsey [184]

Answer:

Option (C)

Step-by-step explanation:

Equation of the quadratic function having vertex at (3, 4) and opening upwards,

So the the minimum point of the function is (3, 4).

Therefore, minimum value of the function is 4 at x = 3.

y = (x - h)² + k [Here, (h, k) is the vertex]

g(x) = 2(x - 4)² + 3

Vertex of the parabola is (4, 3).

Since, leading coefficient is positive, parabola will open upwards.

Therefore, vertex will be the minimum point.

Minimum value of the function will be 3 at x = 4.

Minimum value of the function 'f' is greater than the minimum value of the function 'g'.

Option (C) will be the answer.

6 0
3 years ago
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