All categories

3 years ago

Find the amount accumulated after investing a principle P for T years at an interest rate compounded k times per year.

1 answer:

8 0

1. $3500(1+ \frac{.05}{4}) ^{4*10}$
$3500(1+.0125) ^{40}$
3500(1.64) = 5740

2. $25300(1+ \frac{.045}{12} ) ^{12*25}$
$25300(1+.00375) ^{300}$
25300(3.07) = 77671

Hope that helps. Feel free to ask any questions

You might be interested in

The diagonals of rhombus abcd intersect at point

Anastaziya [24]

C 24 inches im possitive

6 0

3 years ago

Can someone please help me find the answers to these two questions please?

Sliva [168]

Answer:

Question 13: x = 47°

Question 14: x = 67°

Step-by-step explanation:

Question 13:

add up all the known factors meaning 16, 27 and 90°, then subtract 180 from what you got from adding known factors

Question 14:

out out of all numbers meaning 19, 4 and 90°, then subtract 180 from what you got from adding all known factors

5 0

3 years ago

If the expression (3^(d)*\sqrt(5))/(3^(2)*\sqrt(45)) is equal to 3, what is the value of d

Digiron [165]

$3^d\cdot\dfrac{\sqrt5}{3^2\cdot\sqrt{45}}=3\\\\\dfrac{3^d\sqrt5}{3^2\sqrt{9\cdot5}}=3\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\dfrac{3^d\sqrt5}{3^2\sqrt9\cdot\sqrt5}=3\\\\\dfrac{3^d}{3^2\cdot3}=3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{3^d}{3^{2+1}}=3\\\\\dfrac{3^d}{3^3}=3\qquad\text{multiply both sides by}\ 3^3\\\\3^d=3\cdot3^3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\3^d=3^{1+3}\\\\3^d=3^4\iff\boxed{d=4}$

8 0

3 years ago

Consider this expression.

elena55 [62]

Answer:

79 is the value

Step-by-step explanation:

6 0

2 years ago

In ΔMNO, the measure of ∠O=90°, the measure of ∠N=70°, and OM = 3.3 feet. Find the length of MN to the nearest tenth of a foot.

Aleks04 [339]

Answer:

Side MN = 3.5

Step-by-step explanation:

Side NO = 1.2011

Side OM = 3.3

Side MN = 3.51179

Angle ∠M = 20° = 0.34907 rad = π/9

Angle ∠N = 70° = 1.22173 rad = 7/18π

Angle ∠O = 90° = 1.5708 rad = π/2

4 0

3 years ago