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Anvisha [2.4K]
3 years ago
13

Find the amount accumulated after investing a principle P for T years at an interest rate compounded k times per year.

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0
1. 3500(1+ \frac{.05}{4}) ^{4*10}
3500(1+.0125) ^{40}
3500(1.64) = 5740

2. 25300(1+ \frac{.045}{12} ) ^{12*25}
25300(1+.00375) ^{300}
25300(3.07) = 77671

Hope that helps.  Feel free to ask any questions
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write the first six terms of the arithmetic sequence with the first term a1 =90 , and common differnce, d=9​
brilliants [131]
Given a1 = 90
Common difference = adding
90 + 9 = 99, second term
99 + 9 = 108, third term
And keep doing that
You would get
90, 99, 108, 117, 126, 135
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3 years ago
What is the solution to equation? <br><br> 4x+5=2x-3
Masteriza [31]
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Applying Math<br> 8. Solve the equation to<br> show how I = v/r becomes<br> R= v/l Show your work
Sergeu [11.5K]

Answer:

Original  

l = v/r

first multiply each side by r to get it out of the denominator

rl = v

now divide by l to get r by itself

r = l/v

Step-by-step explanation:

Original  

l = v/r

first multiply each side by r to get it out of the denominator

rl = v

now divide by l to get r by itself

r = l/v

4 0
3 years ago
3/7•d=9/14 in this<br> Problem you want to find what d equals
sertanlavr [38]
<u>→ Chapter : Fractions ←</u>
<u><em>≡ We know that:</em></u>
⇔ (\frac{a}{b}) \div (\frac{c}{d})=(\frac{a}{b}) \times (\frac{d}{c})

<u><em>≡ Solution:</em></u>
⇒ (\frac{3}{7}) \times (d)=\frac{9}{14}
⇒ d=(\frac{9}{14}) \div (\frac{3}{7})
⇒ d=(\frac{9}{14}) \times (\frac{7}{3})
∴ \boxed{\frac{3}{2}}
7 0
3 years ago
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Nezavi [6.7K]
 <span>π </span>* 6 = 18.8495559215 / 4 = 4.71238898038
6 0
3 years ago
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