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loris [4]
3 years ago
12

What is the answer to 6+0.10x=0.15x+8

Mathematics
1 answer:
asambeis [7]3 years ago
4 0

Let's solve this problem step-by-step.

6+0.1x=0.15x+8

Step 1: Simplify both sides of the equation.

0.1x+6=0.15x+8

Step 2: Subtract 0.15x from both sides.

0.1x+6−0.15x=0.15x+8−0.15x

−0.05x+6=8

Step 3: Subtract 6 from both sides.

−0.05x+6−6=8−6

−0.05x=2

Step 4: Divide both sides by -0.05.

-0.05x/-0.05=2/-0.05

So, the answer for this problem is x=-40

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<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
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Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
2 years ago
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