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Margarita [4]
3 years ago
10

PLEASE HELP!!!

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

mid point of AC=((2m+2p)/2,(2n+2r)/2)=(m+p,n+r)

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How many solutions are there to the equation below?<br><br> 12x+6=5x
slavikrds [6]

Answer:  There is one solution to the given equation.

Step-by-step explanation:  We are given to find the number of solutions to the following equation :

12x+6=5x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Since the given equation is linear in one variable x, so it will have only one solution.

The solution of equation (i) is given by

12x+6=5x\\\\\Rightarrow 12x-5x=-6\\\\\Rightarrow 7x=-6\\\\\Rightarrow x=-\dfrac{6}{7}.

Thus, there is one solution to the given equation.

7 0
3 years ago
Tickets to a school play cost $2 if bought in advance, and $3 if bought at the door. By selling all 400 of their tickets, $1030
Vitek1552 [10]

Answer:

230 were sold at the door

170 were sold in advance

Step-by-step explanation:

*i dont know if this is the proper way to do it but it has the correct answer

x=at door y=in advance

x+y=400

3x+2y=1030

y=-x+400

2y=-3x+1030

y=-3/2x+515

-x+400=-3/2x+515

x=230 y=170

4 0
3 years ago
Read 2 more answers
∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are
son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

  1. In ΔABC

   ∴ The congruent sides are AB and AC respectively

  • CB =12 ft. 4 in.=148 in.
  • AB=\frac{3}{4}CB =111 in. =9 ft. 3 in.
  • AC=\frac{3}{4}CB =111 in. =9 ft. 3 in.

    ∵  <em>Perimeter of ΔABC</em> =AB+AC+CB

                                        =9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

                                        =30 ft. 10 in.

    2. In ΔDEF

    ∴ The congruent sides are DE and DF respectively

  • DE =  6 ft. 3 in. =75 in.
  • DF =  6 ft. 3 in. =75 in.
  • Let the length of FE is equal to x
  • 0.75FE =DE =DF
  • 0.75x = 6 ft. 3 in. =75 in.
  • x =100 in. =8 ft. 4 in.

   ∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

                                        = 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

                                        = 20 ft. 10 in.

    3. In ΔJKL

    ∴ The congruent sides are JL and KL respectively

  • JK = x+3
  • KL =4x-17
  • JL  =6x-45
  • JL≅KL
  • 4x-17 =6x-45  . . . . . . . . . . . . . . . . . . . . . . . (1)
  • Subracting 4x from both sides from eq 1
  • -17 =2x-45
  • Adding 45 on both the sides
  • 28 =2x
  • Dividing by 2 on both sides
  • 14 =x
  • JK = 14+3 =17
  • KL = 4×14-17 =39
  • JL = 6×14-45 =39

   ∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

6 0
3 years ago
Slope of (17,11)(5,0)
stepladder [879]

Hello from MrBillDoesMath!

Answer:

m = 11/12

Discussion:

Slope of line = m = (change in y) / (change in x)

                      = ( 11 - 0) / (17-5)

                      = 11/12

Thank you,

MrB

6 0
3 years ago
Read 2 more answers
Can you please show me how to do this?
LenaWriter [7]
If you continue the top ray down to the lower our the two lines you create an angle that it's an exterior angle of a triangle and it's also a corresponding angle to the 110° angle. since corresponding angles are congruent this angles is also 110°. this angle makes a linear pair with the angle to it left, the lower right angle on the triangle. linear pairs add to 180° so the angle has to be 70°. the lower left angle of this triangle is given as 37°. since the 3 angles of a triangle must add to 180° , the top angle has to be 180-(70+37)=73. since the top angle of the triangle makes a linear pair with the angle in question, our angle has to be 180-73=107°

8 0
3 years ago
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