Answer:
Step-by-step explanation:
<h3>To prove quadrilateral is a square:</h3>
a) Slope of CB
C(-3,-1) ; B = (0,3)

![\sf = \dfrac{3-[-1]}{0-[-3]}\\\\ =\dfrac{3+1}{0+3}\\\\ = \dfrac{4}{3}](https://tex.z-dn.net/?f=%5Csf%20%3D%20%5Cdfrac%7B3-%5B-1%5D%7D%7B0-%5B-3%5D%7D%5C%5C%5C%5C%20%3D%5Cdfrac%7B3%2B1%7D%7B0%2B3%7D%5C%5C%5C%5C%20%3D%20%5Cdfrac%7B4%7D%7B3%7D)

b) D(1,-4) ; A(4,0)
![Slope \ of \ DA = \dfrac{0-[-4]}{4-1}\\](https://tex.z-dn.net/?f=Slope%20%5C%20of%20%5C%20DA%20%3D%20%5Cdfrac%7B0-%5B-4%5D%7D%7B4-1%7D%5C%5C)


Slope of CB = slope of DA
c) C(-3,-1) ; D(1 , -4)
![\sf Slope \ of \ CD =\dfrac{-4-[-1]}{1-[-3]}](https://tex.z-dn.net/?f=%5Csf%20Slope%20%5C%20of%20%5C%20CD%20%3D%5Cdfrac%7B-4-%5B-1%5D%7D%7B1-%5B-3%5D%7D)


So, CD is perpendicular to CB
d) B(0,3) ; D(1,-4)

e) C(-3,-1) ; A(4,0)
![\sf Slope \ of \ CA = \dfrac{0-[-1]}{4-[-3]}\\](https://tex.z-dn.net/?f=%5Csf%20Slope%20%5C%20of%20%5C%20CA%20%3D%20%5Cdfrac%7B0-%5B-1%5D%7D%7B4-%5B-3%5D%7D%5C%5C)


So, CA is perpendicular to BD

Answer:
20/100=1/5
Step-by-step explanation:
find the gradient of the line to find the fraction
the line is 20 units high so the line starts and stops subtracting equals 20 and the line is 100 units long to get the gradient you find the rise over the run
Answer:
1. D
2. D
Step-by-step explanation:
Answer:
v=ha^2/3
Step-by-step explanation: