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blsea [12.9K]
2 years ago
10

The length of a rectangular piece of cardboard is 2 cm greater than its width. If the length and the width were each decreased b

y 1 cm, the area of the cardboard would be decreased by 27 cm². What are the dimensions of the original piece of cardboard?
Write and solve an equation to represent the problem.
Mathematics
1 answer:
Vladimir [108]2 years ago
8 0

9514 1404 393

Answer:

  13 cm wide;  15 cm long

Step-by-step explanation:

Let w represent the original width. Then the original length is (w+2) and the original area is w(w+2). After the decrease, the width is (w-1) and the length is (w+1). The decreased area is (w-1)(w+1). The difference between these areas is 27, so we have ...

  w(w+2) -(w-1)(w+1) = 27

 w^2 +2w -(w^2 -1) = 27

 2w +1 = 27

  w = (27-1)/2 = 13

The original piece of cardboard was 13 cm wide and 15 cm long.

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Answer:

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Step-by-step explanation:

The data given in the question is:

Mean (μ) = 68.4

Standard Deviation (σ) = 4

Let X denote the height of men. We will use the normal distribution z-score formula to calculate the z-score and then look up the probability in the normal probability distribution table. The z-score formula is:

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P(z<-0.6) = 0.2743

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(b) P(66<X<71)  = P(X<71) - P(X<66)

We need to find P(X<71) so, calculating the z-value:

z = (71-68.4)/4

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(c) To find the probability P(X>71), we need to find P(X<71) and then subtract it from 1 because the normal distribution table gives values for P(X<k). We have already calculated the value of P(X<71) in part (b) so,

P(X>71) = 1 - P(X<71)

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P(X>71) = 0.2578

The probability that the height is more than 71 inches is 0.2578.

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