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blsea [12.9K]
3 years ago
10

The length of a rectangular piece of cardboard is 2 cm greater than its width. If the length and the width were each decreased b

y 1 cm, the area of the cardboard would be decreased by 27 cm². What are the dimensions of the original piece of cardboard?
Write and solve an equation to represent the problem.
Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

9514 1404 393

Answer:

  13 cm wide;  15 cm long

Step-by-step explanation:

Let w represent the original width. Then the original length is (w+2) and the original area is w(w+2). After the decrease, the width is (w-1) and the length is (w+1). The decreased area is (w-1)(w+1). The difference between these areas is 27, so we have ...

  w(w+2) -(w-1)(w+1) = 27

 w^2 +2w -(w^2 -1) = 27

 2w +1 = 27

  w = (27-1)/2 = 13

The original piece of cardboard was 13 cm wide and 15 cm long.

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The temperature is-2 degrees Celsius. If the temperature rises by 15 degrees Celsius, what is the new temperature?
attashe74 [19]

Answer:13

Step-by-step explanation:

7 0
3 years ago
The distance a race car travels is given by the equation d=v0t+12at2 where v0 is the initial speed of the race car, a is the acc
Scrat [10]

Answer:

v0 + 1/2at

Step-by-step explanation: Given that the distance a race car travels is given by the equation d = v0t+12at2 where v0 is the initial speed of the race car, a is the acceleration, and t is the time travelled.

The equation for the driver's average speed s during the acceleration will be:

(v0t+12at2) / t

Since Average speed is equal to distance divided by time.

Therefore, the equation will be:

v0+1/2at

7 0
3 years ago
If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}

now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
3 years ago
What is the y-intercept of the equation of the line that is perpendicular to the line y =
igor_vitrenko [27]

Answer:

y=-5/3x+20

Step-by-step explanation:

Let the equation of the required line be represented as \[y=mx+c\]

This line is perpendicular to the line \[y=\frac{3}{5}x+10\]

\[=>m*\frac{3}{5}=-1\]

\[=>m=\frac{-5}{3}\]

So the equation of the required line becomes \[y=\frac{-5}{3}x+c\]

This line passes through the point (15.-5)

\[-5=\frac{-5}{3}*15+c\]

\[=>c=20\]

So the equation of the required line is \[y=\frac{-5}{3}x+20\]

Among the given options, option 4 is the correct one.

3 0
2 years ago
Help I need one more number but I have no clue what it is!!!!!!!!!!!!!
VARVARA [1.3K]

Answer:

The point of intersection with the x axis are (-2,0) and (8,0)

Step-by-step explanation:

given circle equation x²+y² = 25

x² + y² = r²

r is the radius.

✓(25) = 5

given the center is at (3,0) and radius of 5

(3+5,0) and (3-5,0)

(8,0) and (-2,0)

(Please heart the answer if you find it helpful, it's a motivation for me to help more people)

7 0
3 years ago
Read 2 more answers
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