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blsea [12.9K]
3 years ago
10

The length of a rectangular piece of cardboard is 2 cm greater than its width. If the length and the width were each decreased b

y 1 cm, the area of the cardboard would be decreased by 27 cm². What are the dimensions of the original piece of cardboard?
Write and solve an equation to represent the problem.
Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

9514 1404 393

Answer:

  13 cm wide;  15 cm long

Step-by-step explanation:

Let w represent the original width. Then the original length is (w+2) and the original area is w(w+2). After the decrease, the width is (w-1) and the length is (w+1). The decreased area is (w-1)(w+1). The difference between these areas is 27, so we have ...

  w(w+2) -(w-1)(w+1) = 27

 w^2 +2w -(w^2 -1) = 27

 2w +1 = 27

  w = (27-1)/2 = 13

The original piece of cardboard was 13 cm wide and 15 cm long.

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Answer:

Step-by-step explanation:

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The big triangle as a whole is a 30-60-90. The side length across from the 30 degree angle is 10, so the whole length of BD is 10√3. However, since we already have the length of BC as 10, then segment CD measures

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4 0
3 years ago
Sole for y<br> k = p/2(y+w)<br> y =
mojhsa [17]

Answer:

<u>Answer</u><u>:</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>(</u><u>2</u><u>k</u><u> </u><u>-</u><u>pw</u><u>)</u><u>/</u><u>p</u>

Step-by-step explanation:

k =  \frac{p}{2} (y + w)

multiply 2 on both sides:

k \times 2 = 2 \times  \frac{p}{2} (y + w) \\  \\ 2k = p(y + w)

open the bracket:

2k = py + pw

subtract pw from both sides:

2k - pw = (py + pw) - pw \\ 2k - pw = py

divide p on both sides:

\frac{2k - pw}{p}  =  \frac{py}{p}  \\  \\ y =  \frac{2k - pw}{p}

4 0
3 years ago
Read 2 more answers
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3 years ago
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Find the area of the following shape.
ad-work [718]

Answer:

57 units^2

Step-by-step explanation:

First find the area of the triangle on the left

ABC

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A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5

Then find the area of the triangle on the right

DE

It has a base AC which is  6 units and a height of 1 units

A = 1/2 bh = 1/2 ( 6) *1  = 3

Then find the area of the triangle on the top

It has a base AC which is  3 units and a height of 3 units

A = 1/2 bh = 1/2 ( 3) *3  = 9/2 = 4.5

Then find the area of the rectangular region

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goldfiish [28.3K]

Complete question:

Rich is comparing the cost of maintaining his car with the depreciation value of the car.

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8 0
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