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2 years ago

13 One function of a movie projector is to enlarge the image on the film. This procedure is an example of a

Mathematics

1 answer:

valkas [14]2 years ago

4 0

Dilation because the change of size

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The probability for success of an event is P(A), and the probability of success of a second, independent event is P(B). What is

Alborosie

Given:

The probability for success of an event is P(A)

The probability of success of a second, independent event is P(B).

To find:

The probability of both events occurring, in that order.

Solution:

If A and B are two independent events, then

$P(A\cap B)=P(A)\cdot P(B)$

It is given that,

The probability for success of an event is P(A)

The probability of success of a second, independent event is P(B).

Since A and B both are independent event and we need to find the probability of both events occurring, in that order, i.e., $P(A\cap B)$ , therefore $P(A\cap B)=P(A)\cdot P(B)$ .

Hence, the correct option is A.

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3 years ago

A professor is interested in the average length of books in her library. She has divided her books into a few different categori

natka813 [3]

Answer:I would rather be playing Minecraft

Step-by-step explanation:

I like Minecraft

8 0

3 years ago

Read 2 more answers

A boy needs to grill 13 pounds of meat for a cookout. Determine the Maximum cost per pound that he can afford if he wants to spe

marissa [1.9K]

Answer:

$5.38 per pound

Step-by-step explanation:

70/13=5.384615

5.38x13=69.94

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3 years ago

PLZ IM BEGGING YOU

antoniya [11.8K]

Answer:

200

Step-by-step explanation:

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2 years ago

A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the

Stells [14]

Answer:

$\frac{5}{3}$ in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box= $L\times B\times H$

Substitute the values then we get

Volume of box=V(x)= $(8-2x)(15-2x)x=(15x-2x^2)(8-2x)$

$V(x)=120x-30x^2-16x^2+4x^3$

$V(x)=4x^3-46x^2+120x$

Differentiate w.r.t x

$V'(x)=12x^2-92x+120$

$V'(x)=0$

$12x^2-92x+120=0$

$3x^2-23x+30=0$

$3x^2-18x-5x+30=0$

$3x(x-6)-5(x-6)=0$

$(x-6)(3x-5)=0$

$x-6=0\implies x=6$

$3x-5=0\implies x=\frac{5}{3}$

Again differentiate w.r.t x

$V''(x)=24x-92$

Substitute x=6

$V''(6)=24(6)-92=52>0$

Substitute x=5/3

$V''(5/3)=24(5/3)-92=-52$

Hence, the volume is maximum at x= $\frac{5}{3}$

Therefore, the side of the square , $x=\frac{5}{3}$ in cutout that gives the box the largest possible volume.

5 0

2 years ago