Answer:
Consider points (0, -5) and (-6, -1)
» General equation of a line:
- m is slope
- c is y-intercept
<u> </u><u>S</u><u>l</u><u>o</u><u>p</u><u>e</u><u> </u><u>(</u><u>m</u><u>)</u><u>:</u>
<u> </u><u>y</u><u>-</u><u>i</u><u>n</u><u>t</u><u>e</u><u>r</u><u>c</u><u>e</u><u>p</u><u>t</u><u> </u><u>(</u><u>c</u><u>)</u><u>:</u>
consider point (0, -5)
Equation:
Answer:
(-1/2, 1)
Step-by-step explanation:
I just used the midpoint formula, and plugged in the points. I hope this helps!
=(x^2+x^1 /2 , y^2+y^1 /2)
=(-2+1 /2 , -5+3 /2)
=(-1/2, 1)
Since this point is located in the fourth quadrant you have to rotate it 270 degrees counterclockwise which would end up being in third quadrant. which means the new point would be (-6,-9)