Answer:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Step-by-step explanation:
For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Answer:

Step-by-step explanation:

Is there any other info to this??
The angle m∠AFE is 128 degrees.
<h3>How to find angles?</h3>
∠AFB ≅ ∠EFD
∠EFD = 5x + 6
m∠DFC = (19x - 15)°
m∠EFC = (17x + 19)°
m∠AFE = ?
m∠AFB + m ∠EFD + m∠AFE = 180
Therefore,
5x + 6 + 5x + 6 + m∠AFE = 180
5x + 5x + 6 + 6 + m∠AFE = 180
10x + 12 + m∠AFE = 180
10x + m∠AFE = 180 - 12
10x + m∠AFE = 168
m∠AFE = 168 - 10x
m∠EFC = m ∠EFD + m∠DFC
17x + 19 = 5x + 6 + 19x - 15
17x - 5x - 19x = 6 - 15 - 19
-7x = - 28
x = 28 / 7
x = 4
Therefore,
m∠AFE = 168 - 10x
m∠AFE = 168 - 10(4)
m∠AFE = 168 - 40
m∠AFE = 128°
Therefore, the angle m∠AFE = 128°
learn more on angles here: brainly.com/question/13212279
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A: cost= 3*55+.35m
B: cost=3*50+.40m
set the costs equal, and solve for m.