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yuradex [85]
3 years ago
5

Can anyone help me with part C?

Mathematics
1 answer:
finlep [7]3 years ago
3 0

Answer:430

Step-by-step explanation:78 times 3 is 430

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Suppose X and Y are random variables with joint density function. f(x, y) = 0.1e−(0.5x + 0.2y) if x ≥ 0, y ≥ 0 0 otherwise (a) I
Hatshy [7]

a. f_{X,Y} is a joint density function if its integral over the given support is 1:

\displaystyle\int_{-\infty}^\infty\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=\frac1{10}\int_0^\infty\int_0^\infty e^{-x/2-y/5}\,\mathrm dx\,\mathrm dy

=\displaystyle\frac1{10}\left(\int_0^\infty e^{-x/2}\,\mathrm dx\right)\left(\int_0^\infty e^{-y/5}\,\mathrm dy\right)=\frac1{10}\cdot2\cdot5=1

so the answer is yes.

b. We should first find the density of the marginal distribution, f_Y(y):

f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\frac1{10}\int_0^\infty e^{-x/2-y/5}\,\mathrm dy

f_Y(y)=\begin{cases}\dfrac15e^{-y/5}&\text{for }y\ge0\\\\0&\text{otherwise}\end{cases}

Then

P(Y\ge8)=\displaystyle\int_8^\infty f_Y(y)\,\mathrm dy=e^{-8/5}

or about 0.2019.

For the other probability, we can use the joint PDF directly:

P(X\le5,Y\le8)=\displaystyle\int_0^5\int_0^8f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=1+e^{-41/10}-e^{-5/2}-e^{-8/5}

which is about 0.7326.

c. We already know the PDF for Y, so we just integrate:

E[Y]=\displaystyle\int_{-\infty}^\infty y\,f_Y(y)\,\mathrm dy=\frac15\int_0^\infty ye^{-y/5}\,\mathrm dy=\boxed5

5 0
3 years ago
F(x)= 4x+1 and g(x)=x^2-5 find (f/g) (x)
Georgia [21]
The answer to the question

7 0
3 years ago
True or False? Def is a right triangle.
myrzilka [38]

Answer:

Step-by-step explanation:

We can determine if the triangle is a right triangle by using the Pythagorean theorem

a^2 +b^2 = c^2  where a and b are the legs and c is the hypotenuse

25^2 + 27^2 = 48^2

625+729=2304

1354 ≠2304

This is not true, so this is not a right triangle

7 0
3 years ago
Read 2 more answers
Help me in math please
AURORKA [14]
The answer would be D. y=-2x+8
6 0
4 years ago
Read 2 more answers
For <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%204x%2B1" id="TexFormula1" title="f(x) = 4x+1" alt="f(x) = 4x+1" align="abs
Kamila [148]

\bf \begin{cases} f(x)=4x+1\\ g(x)=x^2-5\\[-0.5em] \hrulefill\\ (f\circ g)(4)=f(~~g(4)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ g(4)=(4)^2-5\implies g(4)=16-5\implies \boxed{g(4)=11} \\\\\\ f(~~g(4)~~)\implies f(11)\implies f(11)=4(11)+1\implies \blacktriangleright f(11)=45\blacktriangleleft

3 0
3 years ago
Read 2 more answers
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