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If correct ill give brainlist

Lilit [14]

Answer:

x> y-300/12

Step-by-step explanation

1. Subtract 300 from both sides

2. Divide both sides by -12

3. Switch the sides

8 0

3 years ago

show how to multiply 6x298 using friendly numbers and then using properties and mental math.write about which method you like be

Mnenie [13.5K]

Multiply 300 times 5. you know that 3 times 5 equals 15. 15 plus 2 zeros is 1500. 1500 is the estimated answer

4 0

3 years ago

West ridge highschool is holding an honor roll banquet. It costs $95 to rent the cafeteria plus $13 for each person attending th

Art [367]

Answer: C(x) = 13x +95

Step-by-step explanation:

Here's the remainder of the question:

If C(x) represents the total cost and x represents the number of people attending the banquet, which equation shows the total cost? A C(x)=95x – 13 B C(x)=13x – 95 C C(x)=95x +13 D C(x)=13x +95

Based on the information given in the question, the total cost will be:

= 95 + 13(x)

= 95 + 13x

Therefore, the correct answer will be C(x)=13x +95

5 0

3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

3x+6-2 = 6x-(7/2*9/0)<br>

kvv77 [185]

$3x+6-2 = 6x-( \frac{7}{2} \times \frac{9}{0} ) \\ \\ 3x + 4 = 6x - \frac{63}{0} \\ \\ 3x + 4 = 6x - 0 \\ \\ 4 + 0 = 6x - 3x \\ \\ 3x = 4 \\ \\ x = \frac{4}{3} .$

The value of x is 4/3 .

5 0

2 years ago

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