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Ivanshal [37]
2 years ago
8

the diameter of the earth at the equator is about 8,000 mi. Based on this figure ,how far is it exactly around the earth

Mathematics
2 answers:
Brrunno [24]2 years ago
8 0
Basically, we want to find the circumfernece of the earth
C=pid
d=diameter
pi=pi (aprox pi=3.1419256)
C=3.14159256*8000
C=25132.74048 feet
geniusboy [140]2 years ago
8 0
C = 2 π r
C = 8,000 π or 25,133 miles
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Please please please please please please please help
Ilia_Sergeevich [38]

Answer:

a. 90 pack

b. $0.27

c. $0.18

d. $0.21

e. 60 pack

Step-by-step explanation:

a. i think  the 90 pack container should be having least unit rate per pack,as purchasing in bulk amount the cost of a unit should be reduced to some amount which is must to lure the customer to purchase in bulk amounts.

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2 years ago
Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.
SashulF [63]

<u>ANSWER</u>

{r}^{2}  = 4  \cos2\theta

<u>EXPLANATION</u>

The Cartesian equation is

{( {x}^{2}  +  {y}^{2} )}^{2}  = 4( {x}^{2} -  {y}^{2}  )

We substitute

x = r \cos( \theta)

y = r \sin( \theta)

and

{x}^{2}  +  {y}^{2}  =  {r}^{2}

This implies that

{( {r}^{2} )}^{2}  = 4(( { r \cos\theta)  }^{2} -  {(r \sin\theta) }^{2}  )

Let us evaluate the exponents to get:

{r}^{4}  = 4({  {r}^{2} \cos^{2}\theta } -   {r}^{2}  \sin^{2}\theta)

Factor the RHS to get:

{r}^{4}  = 4{r}^{2} ({   \cos^{2}\theta } -   \sin^{2}\theta)

Divide through by r²

{r}^{2}  = 4 ({   \cos^{2}\theta } -   \sin^{2}\theta)

Apply the double angle identity

\cos^{2}\theta -\sin^{2}\theta=  \cos(2 \theta)

The polar equation then becomes:

{r}^{2}  = 4  \cos2\theta

7 0
3 years ago
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