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Vladimir79 [104]
3 years ago
6

No links please! Which expression has the same value as Look below

Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer:

-5 1/3 - 3 1/3

Step-by-step explanation

both expressions equal -8 2/3

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Ma= P2-P1/t solve for p1​
natulia [17]

Answer:

P1 =  P2 - ma*t

Step-by-step explanation:

ma= P2-P1/t

we multiply by t both sides of the equation

ma*t = (P2 - P1)*t/t

ma*t = P2 - P1

we sum by P1 both sides of the equation:

P1 +ma*t = P2 - P1 +P1

We ave:

P1 + ma*t = P2

we subtract by ma*t both sides of the equation:

P1 + ma*t -ma*t = P2 - ma*t

finally we have:

P1 =  P2 - ma*t

3 0
3 years ago
Solve 2^x+1=1/8<br> The solution is x =
4vir4ik [10]
It might be X € R but I am not sure
7 0
3 years ago
An object launched straight puwar from the ground level wiht an initional velocity of 32 feet per second.The formula H=32T-16T^2
Dima020 [189]

Answer:

2 secs after

Step-by-step explanation:

Given the height of the object modeled by the eqaution;

H(t) = 32T - 16T² where;

T is the time in seconds

The object hits the ground when h(t)= 0

Substitute H = 0 into the equation and get t as shown;

0 =  32T - 16T²

0-32T = -16T²

-32T = -16T²

32T = 16T²

32 = 16T

T = 32/16

T = 2secs

Hence the object hits the ground after 2 secs

6 0
3 years ago
4/9 + 1/4 divided by 5/6
Hoochie [10]
Use order of operations (PENDAS)to divide 1/4 by 5/6 (remember to use the reciprocal of the second number). Than find GCF with that number you have now and 4/9 to get your answer.
6 0
3 years ago
Read 2 more answers
The temperature at a ski resort dropped from 6 Celsius to -5 Celsius.
Bezzdna [24]
<span>The temperature at a ski resort dropped from 6 Celsius to -5 Celsius.  Suppose we are to calculate the magnitude of the drop.  That would be |6-(-5)| = 11 degrees C.  The actual change in temp was -11 deg. C.</span>
7 0
3 years ago
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