A'(3, 2 ), B'(6, 6 ),C'(6, - 3 )
A translation of 2 units right is equivalent to adding 2 to the x- coordinate with no change to the y- coordinate.
A(1, 2 ) → A'(1 + 2, 2 ) → A'(3, 2 )
B(4, 6 ) → B'( 4 + 2, 6 ) → B'(6, 6 )
C(4, - 3 ) → B'(4 + 2, - 3 ) → B'(6, - 3 )
Answer:
=0.065x10−0.1
Step-by-step explanation:
(1.3x10−2)(0.05)
=(1.3x10+−2)(0.05)
=(1.3x10)(0.05)+(−2)(0.05)
=0.065x10−0.1
Answer:
The car will have lost it's total value by 2007.
Step-by-step explanation:
If initially the car was valued at 44,000$, and after 9 years it's value dropped to 15,000$, we can say that the car's value dropped in 29,000$. If we suppose that the drop is the same every year, we can say that it was of 3,222,2$ by each year.
This amount of money is the 7,3% of the initial value of the car (I multiplied 3,222,2 x 100 : 44,000).
a) The annual rate of change was of 7,3%.
b) There are 14 years between 1993 and 2007. If we multiply 7,3% by 14, we get that the car lost 102,2% of it's initial value.
Answer:
$13,200
Step-by-step explanation:
Depreciation is the systematic allocation of the cost of an asset to the income statement over the estimated useful life of that asset.
It is determined as the depreciable value of the asset over the estimated useful life of the asset where the depreciable value is the difference between the cost and salvage value of the asset
Mathematically,
Depreciation = (Cost - Salvage value)/Estimated useful life
Depreciation
= ($212,000 - $14,000)/15
= $198,000/15
= $13,200
Answer:
8
Step-by-step explanation:
add ur positives
3+3+4=10
now add ur negative
10+ (-2)
8
