Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
Hey There the Answer to this is x = nickels
y= dimes
x + y = 34
.05x + .10y= $1.90
-.10x - .10y = -3.40
-.05x + .10y = 1.90
-.05x = -1.50
x = 30 nickels
30 + y = 34
y = 4 dimes
(3,4) And that you get the answer.
Hope it helps!
Answer:
13 units
Step-by-step explanation:
D is at (1,6) and C is at (-4,-6)
The distance is found by
d = sqrt(( y2-y1)^2+ (x2-x1)^2))
= sqrt( ( -6-6)^2 + (-4-1)^2)
= sqrt( -12^2 + -5^2)
= sqrt( 144+ 25)
= sqrt( 169)
= 13
11 cubic feet is the answer
