If a flying disk is 139 meters in the air and travels at an average of 13 m/s how long is it in the air
2 answers:
Around 10.7s
However I'm not sure what you're really asking for.
How long does it remain in the air?
To find the time it has remained in the air,we can use the formula:
Distance/speed = time
In this case:
139/13
=10.6923...
≈10.69 seconds
Therefore the answer is 10.69 seconds.
Hope it helps!
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Answer:
25/12
Step-by-step explanation:
1/2 + 2/5s = s - 3/4
2/5s = s - 5/4
-3/5s = -5/4
s = 25/12
It would be d if the markup was that high
7x+2=23
Move 2 to the other side
7x=23-2
7x=21
To isolate the x divide both sides by 7
x=3
To check plug the value of x back in
7(3)+2=23
21+2=23
23=23
Now,
b + 40° = 90° ( right angle )
or, b = 90° - 40°
◆ b = 50°
B) 50°
This is Right answer...
I hope it's help you...
Thanks♥♥
The answer to number 1 is B
