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ZanzabumX [31]
3 years ago
10

3n^2-1 find the 2nd and 5th term

Mathematics
2 answers:
Butoxors [25]3 years ago
7 0

Answer:

2nd term = 11

5th term = 74

Step-by-step explanation:

3n² - 1

n = 2 , 2nd term = 3*2²  - 1

                           = 3*4 -1

                          = 12 - 1

                          = 11

n= 5 , 5th term = 3*5² - 1

                        = 3*25 - 1

                      = 75 - 1

                      = 74

user100 [1]3 years ago
5 0

Step-by-step explanation:

in\tt{3n^2-1  } ⠀

If n=2

so,

2nd term=⠀

\rightsquigarrow \tt{3×2^2-1  } ⠀

\rightsquigarrow \tt{ 3×4-1 } ⠀

\rightsquigarrow \tt{ 12-1 } ⠀

\rightsquigarrow \tt{ 11 } ⠀

<h3>so,2nd term is 11.</h3><h3 />

If n=5

so,

5th term =

\rightsquigarrow \tt{ 3×5^2-1 } ⠀

\rightsquigarrow \tt{ 3×25-1 } ⠀

\rightsquigarrow \tt{75-1  } ⠀

\rightsquigarrow \tt{74  }

<h3>so 5th term is 74.⠀</h3>
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A similar problem is given at brainly.com/question/12166019

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