Answer:
31 and 13
Step-by-step explanation:
31+13=44 and 13+18=31 so they are 18 apart
The transformations that would prove that circles A and C are similar are:
- A. Reflect A over the line y=x
- C. Dilate A by 3/2
<h3>How to prove that circle A and circle C are similar?</h3>
The circles are given as:
Circle A and B
Assume the following parameters:
- The center of circle A is (2,3) with a radius of 2
- The center of circle B is (3,2) with a radius of 3
To start with;
The circle A must be reflected across the line y = x with the following transformation rule:
(x,y) -> (y,x)
So, we have:
(2,3) -> (3,2)
Next, the radius of A must be dilated by 3/2 as follows:
New Radius = 3/2 * 2 = 3
After the transformations, we have the following parameters:
- The center of circle A is (3,2) with a radius of 3
- The center of circle B is (3,2) with a radius of 3
Notice that both circles now have the same center and radius.
Hence, both circles are similar
Read more about similar circles at:
brainly.com/question/9177979
The question is incomplete. The complete question is :
Nate starts a lawn-mowing business. In his business, he has expenses and revenue. Nate's expenses are the cost of the lawn mower and gas, and his revenue is $25 per lawn. At what point will Nate's revenue exceed his expense?
Cost of lawn mower = $ 200
Cost of gasoline = $ 2 per lawn
Solution :
Given :
Cost of the lawn mower = $ 200
The cost of gasoline expense for one lawn = $ 2
The revenue generated for one lawn = $ 25
So let the number of lawn to be mowed = x
Therefore the total expenses = 
So, the total revenue = 
The point for which the revenue will exceed the total expenditure will be :
So at 
Thus the revenue exceeds the total expenditure after mowing 9 number of lawns.
Answer:
y ≈ 16.33
Step-by-step explanation:
∆SPQ is a 30-60-90 right triangle
PS:QS:PQ = 1:2:√3
QS/PQ = 2/√3
QS/PQ = QS/10
QS/10 = 2/√3 Multiply each side by 10
QS = 20/√3
∆RSQ is a 45-45-90 right triangle.
∴ RS = QS = 20/√3
RS² + QS² = QR²
(20/√3)² + (20/√3)² = y²
400/3 + 400/3 = y²
800/3 = y² Take the square root of each side
y = √(800/3)
= 20√(2/3)
= (20√6)/3
≈ 16.33
R
12-5
r
7 -> That's true once 7+5
12 = 12
12
or
7/9<0 That's not true once 7/9>0
