Helpppp please... need to get this doneeee

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

3 0

Answer:

if this is iready

Step-by-step explanation:

the answer is

the third one

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$2.25
$2.25
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How do you solve this

AlladinOne [14]

Answer:

domain: all terms are defined for <em>all real numbers</em>
solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6$