Which of the following liquids is basic?

Referring to an activity series, which of the following combinations of reactants would not produce a successful single-replacem

loris [4]

I believe the answer is Ca + MgSO4

8 0

3 years ago

Read 2 more answers

What is the pH of a 0.100 M HI solution? Is that neutral, acidic, or basic? acidic What is the pOH of a 0.100 M HI solution? Is

inessss [21]

Answer: The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

Explanation:

There are three types of solution: acidic, basic and neutral

To determine the type of solution, we look at the pH values.

The pH range of acidic solution is 0 to 6.9
The pH range of basic solution is 7.1 to 14
The pH of neutral solution is 7.

We are given:

Concentration of HI = 0.100 M

1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.100M$

Putting values in above equation, we get:

$pH=-\log(0.100)\\\\pH=1$

To calculate the pOH of the solution, we use the equation:

pH + pOH = 14

$pOH=14-1=13$

Hence, the pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

4 0

3 years ago

4. What is the role of the benedict solution in testing for presence of carbohydrates

Vanyuwa [196]

Answer:

it identifies reducing sugars (monosaccharide's and some disaccharides), which have free ketone or aldehyde functional group

Explanation:

It turns from turquoise to yellow or orange when it reacts with reducing sugars.

3 0

2 years ago

A gas evolved during the fermentation of alcohol had a volume of 19.4 L at 17 °C and 746 mmHg. How many moles of gas were collec

AlexFokin [52]

Answer:- 0.800 moles of the gas were collected.

Solution:- Volume, temperature and pressure is given for the gas and asks to calculate the moles of the gas.

It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:

PV=nRT

Since it asks to calculate the moles that is n, so let's rearrange this for n:

$n=\frac{PV}{RT}$

V = 19.4 L

T = 17 + 273 = 290 K

P = 746 mmHg

we need to convert the pressure from mmHg to atm and for this we divide by 760 since, 1 atm = 760 mmHg

$P=746mmHg(\frac{1atm}{760mmHg})$

P = 0.982 atm

R = $0.0821\frac{atm.L}{mol.K}$

Let's plug in the values in the equation to get the moles.

$n=\frac{0.982atm*19.4L}{0.0821\frac{atm.L}{mol.K}*290K}$

n = 0.800 moles

So, 0.800 moles of the gas were collected.

4 0

3 years ago

You carefully weigh out 16.00 g of CaCO3 powder and add it to 64.80 g of HCl solution. You notice bubbles as a reaction takes pl

bulgar [2K]

Answer: Mass of $CO_2$ produced in this reaction was 6.56 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$CaCO_3(s)+2HCl(aq)\rightarrow H_2O(l)+CO_2(g)+CaCl_2(aq)$

Mass or reactants = Mass of $CaCO_3$ + mass of $HCl$ = 16.00 + 64.80 = 80.80 g

Mass of products = mass of aqueous solution + mass of $CO_2$ + = 74.24 + x g

Mass or reactants = Mass of products

80.80 g = 74.24 + x g

x = 6.56 g

Thus mass of $CO_2$ produced in this reaction was 6.56 grams

7 0

3 years ago