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2 years ago

PLEASE HELP ITS MAJOR

Chemistry

2 answers:

8_murik_8 [283]2 years ago

8 0

Explanation:

solid and has black they are 3 states.

Charra [1.4K]2 years ago

3 0

Answer:

solid, liquid

Explanation:

solid liquid and gas are the three most common states of matter, my best guessstimation is that solid is the ¨normal form¨ with you having to then heat it up to get to gas or, change it to liquid... even though most of the earth is liquid soo it could also be liquid try your best and think it over

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If I have 22,9 moles of a gas at a pressure of 12.4 atm and a volume of 24 liters, what is the temperature?

Grace [21]

Answer:

160 K, using 2 SF,

Explanation:

Ideal Gas law, rearrange to solve for T (K), answer about 158.3 round to 2SF

PV = nRT

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2 years ago

Using table 9.4, calculate an approximate enthalpy (in kj) for the reaction of 1.02 g gaseous methanol (ch3oh) in excess molecul

Tanya [424]

Given:

Mass of methanol = 1.02 g

To determine:

Enthalpy for the reaction of 1.02 g of methanol with excess O2

Explanation:

Balanced equation-

2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)

The reaction enthalpy is given as:

ΔHrxn = ∑nH°f(products) - ∑nH°f(reactants)

where n = number of moles

H°f = standard enthalpy of formation.

ΔHrxn = [2H°f(CO2(g)) + 4H°f(H2O(g))] - [2H°f(CH3OH(g)) + 3H°f(O2(g))]

= [2(-393.5) + 4(-241.8)]-[2(-201.5) + 3(0)] = -1351.2 kJ

Now, 1 mole of CH3OH = 32 g

The calculated ΔHrxn corresponds to 2 moles of CH3OH. i.e.

The enthalpy change for 64 g of Ch3OH = -1351.2 kJ

Therefore, for 1.02g gaseous methanol we have:

ΔH = 1.02 * -1351.2/64 = -21.5 kJ

Ans: The enthalpy for the given reaction is -21.5 kJ

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3 years ago

Protons are positively charged and repel other protons. Which order particle is found in the nucleus and separates protons so th

jenyasd209 [6]

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3 years ago

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tangare [24]

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3 years ago

Read 2 more answers

Select the pair that consists of a base and its conjugate acid in that order. CO32−/CO22−

lana [24]

Answer: The pair that consists of a base and its conjugate acid in that order. $NH_3/NH_4^+$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

$H_3PO_4\rightarrow H_PO_4{2^-}+2H^+$

$H_2CO_3\rightarrow HCO_3^-+H^+$

$NH_3+H^+\rightarrow NH_4^+$

$HCO_3^-\rightarrow CO_3^{2-}+H^+$

$NH_3$ is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms $NH_4^+$ which is a conjugate acid.

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3 years ago