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Volgvan
2 years ago
7

Hydrogen and chlorine atoms react to form a simple diatomic molecule in a 1:1 ration, that is HCl. The percent isotopic abundanc

es of the chlorine isotopes 35Cl and 37Cl are 75.77% and 24.23%, respectively. The percent isotopic abundances of the hydrogen isotopes are 2H and 3H are 0.015% and 0.001%. (a) How many different HCl molecules are possible, and what are their mass numbers
Chemistry
1 answer:
Sergio [31]2 years ago
6 0

Answer:

Four different HCl molecules are possible.

  1. Mass of ^{2}H^{35}Cl  = 37 amu
  2. Mass of ^{3}H^{35}Cl =  38 amu
  3. Mass of ^{2}H^{37}Cl = 39 amu
  4. Mass of ^{3}H^{37}Cl = 40 amu

Explanation:

Mass of 2-H isotope = 2 amu

Mass of 3-H isotope = 3 amu

Mass of 35-Cl isotope = 35 amu

Mass of 37-Cl isotope = 37 amu

Different HCl molecules possible are:

1) ^2H+^{35}Cl\rightarrow ^{2}H^{35}Cl

Mass of ^{2}H^{35}Cl = 2 amu + 35 amu = 37 amu

2)  ^3H+^{35}Cl\rightarrow ^{3}H^{35}Cl

Mass of ^{3}H^{35}Cl = 3 amu + 35 amu = 38 amu

3) ^2H+^{37}Cl\rightarrow ^{2}H^{37}Cl

Mass of ^{2}H^{37}Cl = 2 amu + 37 amu = 39 amu

4) ^3H+^{37}Cl\rightarrow ^{3}H^{37}Cl

Mass of ^{3}H^{37}Cl = 3 amu + 37 amu = 40 amu

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posledela

The question is incomplete, here is the complete question:

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag

Suppose 6 moles of silver nitrate react. The reaction consumes___ moles of copper. The reaction produces __ moles of copper(II) nitrate and __ moles of silver.

<u>Answer:</u> The amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

<u>Explanation:</u>

We are given:

Moles of silver nitrate = 6 moles

For the given chemical reaction:

2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag

  • <u>For copper metal:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of copper metal

So, 6 moles of silver nitrate will react with = \frac{1}{2}\times 6=3mol of copper metal

Moles of copper reacted = 3 moles

  • <u>For copper(II) nitrate:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 1 mole of copper(II) nitrate

So, 6 moles of silver nitrate will produce = \frac{1}{2}\times 6=3mol of copper(II) nitrate

Moles of copper(II) nitrate produced = 3 moles

  • <u>For silver metal:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6 moles of silver nitrate will produce = \frac{2}{2}\times 6=6mol of silver metal

Moles of silver metal produced = 3 moles

Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

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This means that a pond can become a bog when existing plants in the pond decays until the land becomes soft.

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Answer:1.

1.Balanced equation

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Explanation:

1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;

CxHy +( x+y/4) O2 ==> y/2 02 + xCO2

Where x and y are number of carbon and hydrogen atoms respectively.

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V= 24.8 × 0.08206 × 293

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