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Volgvan
3 years ago
7

Hydrogen and chlorine atoms react to form a simple diatomic molecule in a 1:1 ration, that is HCl. The percent isotopic abundanc

es of the chlorine isotopes 35Cl and 37Cl are 75.77% and 24.23%, respectively. The percent isotopic abundances of the hydrogen isotopes are 2H and 3H are 0.015% and 0.001%. (a) How many different HCl molecules are possible, and what are their mass numbers
Chemistry
1 answer:
Sergio [31]3 years ago
6 0

Answer:

Four different HCl molecules are possible.

  1. Mass of ^{2}H^{35}Cl  = 37 amu
  2. Mass of ^{3}H^{35}Cl =  38 amu
  3. Mass of ^{2}H^{37}Cl = 39 amu
  4. Mass of ^{3}H^{37}Cl = 40 amu

Explanation:

Mass of 2-H isotope = 2 amu

Mass of 3-H isotope = 3 amu

Mass of 35-Cl isotope = 35 amu

Mass of 37-Cl isotope = 37 amu

Different HCl molecules possible are:

1) ^2H+^{35}Cl\rightarrow ^{2}H^{35}Cl

Mass of ^{2}H^{35}Cl = 2 amu + 35 amu = 37 amu

2)  ^3H+^{35}Cl\rightarrow ^{3}H^{35}Cl

Mass of ^{3}H^{35}Cl = 3 amu + 35 amu = 38 amu

3) ^2H+^{37}Cl\rightarrow ^{2}H^{37}Cl

Mass of ^{2}H^{37}Cl = 2 amu + 37 amu = 39 amu

4) ^3H+^{37}Cl\rightarrow ^{3}H^{37}Cl

Mass of ^{3}H^{37}Cl = 3 amu + 37 amu = 40 amu

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nasty-shy [4]

The boiling point of HF is higher than the boiling point of H_2, and it is higher than the boiling point of F_2.

<h3>What is the boiling point?</h3>

The boiling point is the temperature at which the pressure exerted by the surroundings upon a liquid is equalled by the pressure exerted by the vapour of the liquid.

F_2 has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions between H^+ and F^- ions.

Only London Forces are formed - Therefore more energy is required to break the intermolecular forces in HF than in the other hydrogen halides and so HF has a higher boiling point.

H_2 and F_2 will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.

Hence, the boiling point of HF is higher than the boiling point of H_2, and it is higher than the boiling point of F_2.

Learn more about the boiling point:

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7 0
1 year ago
PLEASE HELP ME, 20 POINTS
Marrrta [24]

Explanations:

<u>Question</u> <u>1:</u> Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

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4 0
2 years ago
Question: Draw a valid Lewis structure for the molecule CH3NO in which there are no nonzero formal charges on any of the atoms.
iVinArrow [24]

The mentioned molecule with formula, CH₃NO where no bond is found between N and O can be depicted as formamide is shown in the attachment below.  

The formal charges = Number of valence electrons for the atom (V) - the number of electrons in lone pairs (N) - 1/2 (number of electrons in bond pairs, B)

FC = V - N - B/2

Thus, there is a need to calculate valence electrons, electrons in lone pairs, and the number of electrons in bond pairs for each atom in the mentioned molecule.  

V or valence electrons on C = 4e, on H = 1e, on N = 5e, and on O = 6e.  

N or electrons in lone pairs on C = 0e, on H = 0e, on N = 2e, and on O = 4e.  

B or number of electrons in bond pairs for C = 8e, for H = 2e, for N = 6e, and for O = 4e.  

Thus, the formal charges for each will be,  

C = 4 - 0 - (8/2) = 0

H = 1 - 0 - (2/2) = 0

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Lewis dot structure for the given molecule is given in the attachment below:


3 0
3 years ago
Read 2 more answers
Copper was the first metal to be produced from its ore because it is the easiest to smelt, that is, to refine by heating in the
Ganezh [65]

Answer:

57.48%

Explanation:

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MM O = 16.00

MM H = 1.01

MM C = 12.01

(Cu_{2}(OH)_{2}CO_{3})

A mole of malachite has:

2 moles of Cu

5 moles of O

2 moles of H

1 mole of C

MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)

MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01

MW Malachite = 221.13

Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1

Now divide the mass of Cu by the mass of Malachite

%Cu = \frac{127.1}{221.13} =0.5748=57.48%

7 0
3 years ago
A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
Sedbober [7]

Answer:

81°C.

Explanation:

To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat released from water (Q = - 1200 J).

m is the mass of the water (m = 20.0 g).

c is the specific heat capacity of water (c of water = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 95.0°C).

∵ Q = m.c.ΔT

∴ (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).

(- 1200 J) = 83.72 final T - 7953.

∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.

<em>So, the right choice is: 81°C.</em>

7 0
3 years ago
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