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Fofino [41]
3 years ago
6

PLS HELP ASAP

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0

Answer:

Pretty sure it's 140.87 cm

Step-by-step explanation:

Multiply 3 1/2 by 4 1/4

Divide by two which is 7.43

Multiply 3 1/2 by 12

Now add 42+42+42+7.43+7.43

OR

126+14.87  

Mamont248 [21]3 years ago
3 0

Answer:

V=94.5 cm^3

Explanation:

Volume of a Prism: (B)H

B=Base Formula

H=Height of Prism

H=12

Triangle Base Formula: 1/2bh

b=3.5

h=4.5

Substitute Variables in formula:

V=[1/2(3.5)(4.5)](12)

Solve:

V=(7.875)(12)

V=94.5 cm^3

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Help me solve problem one please.
max2010maxim [7]

Answer: His temperature is 99°F

Step-by-step explanation:

Let's state what we know:

Steve's temperature was initially 102°F

Later it dropped 3°F lower

Since his temperature decreased we need to subtract 3 from 102 to see what his temperature is now

102-3=99

4 0
2 years ago
In cell e7, create a formula that calculates the salary for sarah, one of the servers at the good breeze hotel. her salary is ca
Cloud [144]

Answer:

The formula: e7 = (b7*d7)+(c7*d7*1.5)

Step-by-step explanation:

Given:

Hours worked = b7

Hourly rate = d7

Overtime hours = c7

Salary calculation = e7

Salary = Hours worked*hourly rate + (overtime*hourly rate)*1.5

Formula

e7 = (b7*d7)+(c7*d7*1.5)

The formula e7 = (b7*d7)+(c7*d7*1.5)

Hope this will helpful to you.

Thank you.

6 0
3 years ago
A concrete patio is 5 2/3 feet wide. It has an area of 36 5/6 square feet. What is the length of the concrete patio
Aneli [31]
The length of the concrete patio is 6 1/2.
I got this answer by dividing 36 5/6 and 5 2/3. Therefore, answer is 6 1/2
4 0
3 years ago
50.38 inches in 2012 in 2013 the annual rainfall was 55.76 inches what is the difference in rainfall between the two years
Leno4ka [110]
55.76-50.38=4.38 inches of rainfall
Your welcome  =)
difference= subtraction
3 0
3 years ago
Not sure what to do here can someone please help
kumpel [21]

Answer:

  x = 2

Step-by-step explanation:

These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.

__

<h3>Squaring</h3>

The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.

  \sqrt{x+2}+1=\sqrt{3x+3}\qquad\text{given}\\\\(x+2)+2\sqrt{x+2}+1=3x+3\qquad\text{square both sides}\\\\2\sqrt{x+2}=(3x+3)-(x+3)=2x\qquad\text{isolate the root term}\\\\x+2=x^2\qquad\text{divide by 2, square both sides}\\\\x^2-x-2=0\qquad\text{write in standard form}\\\\(x-2)(x+1)=0\qquad\text{factor}

The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.

  x = -1: √(-1+2) +1 = √(3(-1)+3)   ⇒   1+1 = 0 . . . . not true

  x = 2: √(2+2) +1 = √(3(2) +3)   ⇒   2 +1 = 3 . . . . true . . . x = 2 is the solution

__

<h3>Substitution</h3>

Another way to solve this is using substitution for one of the radicals. We choose ...

  u=\sqrt{x+2}\qquad\text{requires $u\ge0$}\\\\u^2-2=x\qquad\text{solve for x}\\\\u+1=\sqrt{3(u^2-2)+3}\qquad\text{substitute for x in the original equation}\\\\(u+1)^2=3u^2-3\qquad\text{square both sides, simplify a little}\\\\2u^2-2u-4=0\qquad\text{subtract $(u+1)^2$}\\\\2(u-2)(u+1)=0\qquad\text{factor}

Solutions to this equation are ...

  u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution

The value of x is ...

  x = u² -2 = 2² -2

  x = 2 . . . . the solution to the equation

_____

<em>Additional comment</em>

Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.

6 0
1 year ago
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