Answer:
(- 19, - 11, 5, 25)
Step-by-step explanation:
The given function is f(x) = 4x - 7
Now, we have to find the range of the given function for the given domains.
The domains are given as (2 - 5, - 1, 3, 8) i.e. (- 3, - 1, 3, 8).
Therefore, f(- 3) = 4(- 3) - 7 = - 19
f(- 1) = 4(- 1) - 7 = - 11
f(3) = 4(3) - 7 = 5
f(8) = 4(8) - 7 = 25
So, the ranges of the function are (- 19, - 11, 5, 25) (Answer)
Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
The GCF of 24, 32, and 80 must be 8, since it is the largest number common to both lists. Example 1 Find the greatest common factor of each set of numbers by listing factors.
Answer:
- 321 adult tickets
- 227 child tickets
Step-by-step explanation:
This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...
6.50x +3.50(548-x) = 2881
3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms
3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918
x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3
548-x = 548 -321 = 227 . . . . . .number of child tickets
321 adult tickets and 227 child tickets were sold.
