The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Data;
- Angle = 30 degree
- Opposite = 35
- Adjacent = x
<h3>Trigonometric Ratio</h3>
Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.
SOHCAHTOA
Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.
The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Learn more on trigonometric ratio here;
brainly.com/question/12172664
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answer: 16
how? 100/4 = 25
3/4 = 0.75 because 25 x 3 = 0.75
0.75x = 12
12/0.75 = 16
C = 84 degrees
A = 2B
C = A + 20
A + B + C = 180
A = 2B
A/2 = B
A + (A/2) + (A+20) = 180
multiply each side by 2
2A + A + 2A + 40 = 360
combine like terms
5A + 40 = 360
subtract 40 from both sides
5A = 320
divide both sides by 5
A = 64
C = A + 20
C = 64 + 20
C = 84
Answer:
the initial height of water.
Step-by-step explanation:
when time equals zero, no water has been drained.
the volume of the tank is unknown however the volume in the tank is 12 at time zero
Dory: $11.25= x+x+x+y+y+y or $11.25= (3*x)+(3*y)
Nemo: $10.00=x+x+x+x+y+y or $10.00= (4*x)+(2*y)
<span>This is your answer
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