Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
1) 500 2) $ 1000 debt 3) $350 4) $2500 debt
Step-by-step explanation:
profit = .5x -250
1) O = .5x -250
250 = .5x
500 = x number to break even
2) f(900) = .5 (900) -250 = $200
from the graph g(200) = total debt = $1000
3) f(x) = -75 = .5x-250 results in x = $ 350
4) f(500) = .5(500) - 250 = 0
from the graph, this corresponds to total debt g (f(500) = $2500 debt
Based on this information, what should the company do is that "<span>The expected value is $4,000.00, so the company should proceed with the campaign." The answer is B.
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Answer:
Log₆ (A⁵C² / D⁶) = –13
Step-by-step explanation:
From the question given above,
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
Log₆ (A⁵C² / D⁶) =?
Recall:
Log MN / U = Log M + Log N – Log U
Therefore,
Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶
Recall:
Log Mⁿ = nLog M
Thus,
Log₆ A⁵ + Log₆ C² – Log₆ D⁶
= 5Log₆ A + 2Log₆ C – 6Log₆ D
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
= 5(1) + 2(3) – 6(4)
= 5 + 6 – 24
= 11 – 24
= –13
Therefore,
Log₆ (A⁵C² / D⁶) = –13
Answer:
A. round
Step-by-step explanation:
simple answer, I think you were just joking