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lord [1]
3 years ago
6

Solve for x. x2 + 9x = 0 a 0, -9 b 0, 9 c 1, -9 d 1, 9

Mathematics
1 answer:
alekssr [168]3 years ago
5 0
<span>x2 + 9x = 0
x(x+9) = 0
x=0
x+9 = 0; x = -9

answer is </span><span>a 0, -9</span>
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A bucket is filled with water up to the 4 gallon mark. The bucket springs a leak and water begins draining at a constant rate of
zheka24 [161]

Answer:

n = 4 - \frac{5}{19}t

Step-by-step explanation:

n determines the amount of water in the bucket, it's basically the total, so that's why it's there. 4 is the number of gallons of water that you started with and 5/19 is the number of gallons that are draining per minute.  t is the amount of time or minutes that have gone by. So, that's why the equation is   n = 4 -\frac{5}{19}t

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3 years ago
If 5+ 20 -22-3х - 10.2-2x+5, what is the value of х?
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Answer:

<h2>3</h2>

Step-by-step explanation:

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3 years ago
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ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

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3 years ago
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Answer:

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Step-by-step explanation:

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