Answer:
1) 128
2) 32
Step-by-step explanation:
1) 8C1×4C1×4C1 = 128
2) 5C1 + 5C2 + 5C3 + 5C4 + 5C5
= 32
<u>Options</u>
![(A)\left(-\infty , \dfrac23\right]\\\\(B)\left(-\infty , \dfrac23\right) \\\\(C)(\frac23\right, \infty ) \\\\(D) [\frac23\right, \infty )](https://tex.z-dn.net/?f=%28A%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%5D%5C%5C%5C%5C%28B%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%29%20%5C%5C%5C%5C%28C%29%28%5Cfrac23%5Cright%2C%20%5Cinfty%20%29%20%5C%5C%5C%5C%28D%29%20%5B%5Cfrac23%5Cright%2C%20%5Cinfty%20%29)
Answer:
Step-by-step explanation:
Given the solution to an inequality
{x|x>2/3}
The solution set does not include 
, therefore, it must be open at the left. Recall that we use a curvy bracket ( to denote openness at the left.
Since x is greater than , the solution set contains all values of larger than up till infinity. Since infinity is an arbitrarily large value, we also use an open bracket at the right.
Therefore, another way to represent the solution {x|x>2/3} is:
The correct option is C.
Answer:
The probability of missing both two-point conversion attempts is 7.5%
Step-by-step explanation:
We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time
Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;
50%*15% = 0.5 * 0.15 = 7.5%
Therefore, the probability of missing both two-point conversion attempts is 7.5%
You will need half of the circle with radius of 15 inches.
Area of semi-circle = (<span>πr^2)/2 = 353.25 x $1.40 = $494.55 </span>
