Answer:
16q + 32r
Step-by-step explanation:
Answer:
Solution given:
1.
diameter(d)=6mm
base(b)=8mm
height (h)=5mm
Area of figure=area of parallelogram +area of semi circle
- base*height+½π(d/2)²
- 8*5+½*π×(6/2)²
- 40+14.14
- 54.4mm²
- <u>Area</u><u> </u><u>:</u><u>5</u><u>4</u><u>.</u><u>1</u><u>4</u><u>m</u><u>m</u><u>²</u>
2.
for triangle
base[b]=6ft
height(h)=9ft
for square
length[l]=9ft
Area of figure=area of square +area of triangle
- =l²+½*b*h
- =9²+½*6*9
- =81+27
- =108ft²
- <u>Area</u><u>:</u><u> </u><u>1</u><u>0</u><u>8</u><u>f</u><u>t</u><u>²</u>
Try this solution:
for the circle A: circumference=6π, area=9π
for the circle B: circumference=12π, area=36π
PS. formula for circumference is 'L=2πr', for area is 'S=πr²'.
Answer:
Step-by-step explanation:
so you already have the formula, which is
![\sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
the v represents Volume.
and 3v would be 3×volume.
![\sqrt[3]{ \frac{3 \times 1000}{4 \times \pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%201000%7D%7B4%20%5Ctimes%20%5Cpi%7D%20%7D%20)
![\sqrt[3]{ \frac{3000}{12.56637061} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3000%7D%7B12.56637061%7D%20%7D%20)
![\sqrt[3]{238.7324147 }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B238.7324147%20%7D%20)
to the nearest tenth place.
Pretty sure it’s d(all of the above)
