The black color coat (B) is dominant to brown color (b) and Normal vision (N) is dominant to blindness (n). A cross is formulated between a dog that is heterozygous for coat color and vision with a blind brown dog. The predicted phenotypic ratio of the offspring’s is 25 percent of BbNn, Bbnn, bbNn, Bbnn.
Further Explanation:
Genotype of an organism is referred as genetic makeup. An individual appearance is described by its Phenotype. The phenotype of an organism is depends upon its genotype. If an organism consists of two copies of the identical alleles then the genotype of an organism is called homozygous. If two copies of different alleles present in an organism, its genotype is called heterozygous.
A recessive trait is defined as a trait that gets expressed by an individual, when they show a homozygous recessive condition. This means that if an individual showing a recessive trait will definitely possess both the recessive alleles for that trait as recessive trait gets concealed by the presence of allele for dominant trait.
Black coat allele: B
Brown coat allele: b
Normal vision: N
Blindness: n
A dog that is heterozygous for coat color means it is Bb, and he is heterozygous for the vision trait so, Nn. This dog is black and can visualize. The other dog that is blind and brown means he has the genotype of bbnn. So, the cross is formulated between both the dogs, the genotype of progeny are as following:
BbNn–Twenty five percent dogs are black and normal
Bbnn–Twenty five percent dogs are blind with black coat color.
bbNn-Twenty five percent of dogs has brown coat with normal vision.
Bbnn-Twenty five percent of dogs are blind with brown color vision.
The punnet square of the cross between both the dogs is given below.
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Answer Details:
Grade: High School
Subject: Biology
Chapter: Mendelian Inheritance
Keywords:
Punnet square, genotype, phenotype, homozygous, heterozygous, allele, characteristics, filial generation, dominant, recessive.