Two lines are said to be perpendicular if the product of their slope = -1, that is , if $m_{1}$ is the slope of the first line and $m_{2}$ is the slope of the second line , if the two lines are perpendicular , then $m_{1}$ $m_{2}$ = -1

The equation of the line given :

y = 1/2x - 1

comparing with the equation of line in slope intercept form

y = mx + c , where m is the slope and c is the y - intercept , it implies that

$m_{1}$ = 1/2

Therefore :

$m_{2}$ = -2

To find the equation of the line with slope -2 and passes through the point ( 3 , 4 ) we will use the formula

$y-y_{1}$ = m ( $x-x_{1}$ )

y - 4 = -2 ( x - 3 )

y - 4 = -2x + 6

y = -2x + 6 + 4

y = -2x + 10

7 0

3 years ago

Subtract.<br> (9x2+3x+6)–(8x2+3)

max2010maxim [7]

Answer:

x^2 +3x +3

Step-by-step explanation:

(9x^2+3x+6)–(8x^2+3)

Distribute the negative sign

(9x^2+3x+6)–8x^2-3

Combine like terms

9x^2–8x^2+3x+6–8x^2-3

x^2 +3x +3

3 0

3 years ago