Firstly let's find hypotenuse(let it will be "n" of smaller triangle
Let use Pythagorean theorem
Now we need to find hypotenuse(x) of bigger triangle
The value of x must be rounded to 1 DP, so
Answer: x=24.1
Answer:
- 11040 m³
- k ≈ 0.33
- V = (1/3)Bh
Step-by-step explanation:
The given relation is ...
V = kBh . . . . . for some base area B, height h, and constant of variation k
We are given length and width of the base so we presume it is a rectangle.
B = l·w = 8·11 = 88 . . . . square meters
The given volume tells us the value of k:
1144 = k(88)(39) . . . . . . cubic meters
1144/3432 = k = 1/3 ≈ 0.33
The value of k is about 0.33.
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Then the volume of the larger pyramid is ...
V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³
The general relationship is ...
V = 1/3Bh
Answer:
2(2−1)
Step-by-step explanation:
4−2
Grouping
Common factor
4−2
2(2−1)
Solution
2(2−1)
