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3 years ago

85/100 in simplist form

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

7 0

Answer: 17/20

Step-by-step explanation: To write the fraction 85/100 in lowest terms, we divide the numerator and the denominator by the greatest common factor of 85 and 100 which is 5. If we divide both the numerator and denominator by 5, we get the equivalent fraction 17/20.

svet-max [94.6K]3 years ago

3 0

Answer:

17/20

Step-by-step explanation:

17/20 would be the simplest form.

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Advocard [28]

Answer:

y = 38 + 72t - 16t^2

Step-by-step explanation:

So, solve for t when y=48.

The max height is of course, when t = 64/32 = 2.

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3 years ago

Draw or write to explain why i hundred 4 ten and 14 tens name the same amount

butalik [34]

ten tens are one hundred and then they both have 4 tens or forty

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3 years ago

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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$

The critical values are y = 0 and y = 10.

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3 years ago

Find the mean proportional between 4 and 16.

ludmilkaskok [199]

Answer:

Step-by-step explanation:

4 × 16= 64

√64 = 8

hope this helps...

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3 years ago

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Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.

Alla [95]

Answer with explanation:

The given expression is:

$2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0$

$\cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}$

Option C

8 0

3 years ago