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Paul [167]
3 years ago
14

7x+3y=22 4y=20 I need to know how to write this equation out with the answer

Mathematics
2 answers:
xeze [42]3 years ago
5 0
7x+3y=22
4y=20

4y=20
y=5

Substitute to first equation
7x+15=22
7x=7
x=1
WITCHER [35]3 years ago
3 0
\begin{cases} 7x+3y=22 \\ 4y=20 \ \ /:4 \end{cases}\\ \\\begin{cases} 7x+3 \cdot 5=22 \\ y= 5 \end{cases}\\ \\\begin{cases} 7x+15=22 \ \ |-15 \\ 4y=20 \end{cases}

\begin{cases} 7x+15 -15=22 -15 \\ y=5 \end{cases}\\ \\\begin{cases} 7x =7\ \ / :7 \\ y=5 \end{cases}\\ \\\begin{cases} x =1 \\ y=5 \end{cases}\\ \\


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Find the unit rate for 1/2 mile in 3/10 hour
babunello [35]

Answer:

1 mile for every 0.6 hours

Step-by-step explanation:

0.5 x 2 = 1

3/10 x 2 = 6/10

2 miles = 1.2 hours

4 0
2 years ago
A number line contains points Q, R, S, and T. Point Q is on the coordinate 24, R is on the coordinate 28, S is on the coordinate
const2013 [10]

|\Omega|=QT=42-24=18\\ |A|=ST=42-29=13\\\\ P(A)=\dfrac{13}{18}\approx72.2\%\Rightarrow \text{D}

7 0
3 years ago
Read 2 more answers
A gym charges a monthly fee and an additional cost for each class. Consider the graph that represents the relationship between t
bija089 [108]
For this problem you need to understand that a linear graph is a straight line (Remember Rise/Run). 
A continous function is <span>a </span>continuous function<span> is a </span>function <span>for which sufficiently small changes in the input result in arbitrarily small changes in the output, so we can already cross off that as an answer.
The Y-Intercept is the cost (in dollars), so this would be to monthly fee. 
Now, onto the rate of change. T</span>he rate of change is <span>represented by the slope of a line. So the more classes you take the more it will increase. Therefore the cost for  one class is the rate of change. 
Lastly, the cost for one class is $10. It's not, since $10 is the intial fee to belong to a gym, so this is false. 

Recap:
True
-The relationship is linear
-The y-intercept represents the monthly fee.
-The rate of change represents the cost for one class.
False
-The relationship represents a continuous function. 
-The cost for one class is $10.
I hope I've helped you, have a great day!</span>
7 0
3 years ago
PLEASE HELP I NEED THIS NOW SO BADLY :(( Simplify: 2 1/4 x+(4 1/3 x−7 4/5 )÷2 3/5
prohojiy [21]

Answer:

2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}

Step-by-step explanation:

Considering the expression

2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}

Simplifying the expression

\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{1}{4}=\frac{9}{4}

\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{3}{5}=\frac{13}{5}

\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 4\frac{1}{3}=\frac{13}{3}

\frac{9}{4}x+\left(\frac{13}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 7\frac{4}{5}=\frac{39}{5}

\frac{9}{4}x+\left(\frac{13}{3}x-\frac{39}{5}\right)\div \frac{13}{5}

As

\frac{9}{4}x=\frac{9x}{4}

and

\frac{\frac{13}{3}x-\frac{39}{5}}{\frac{13}{5}}=\frac{5\cdot \frac{65x-117}{15}}{13}

So,

\frac{9x}{4}+\frac{5\cdot \frac{65x-117}{15}}{13}

\mathrm{Least\:Common\:Multiplier\:of\:}4,\:13:\quad 52

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

\frac{117x}{52}+\frac{\frac{4\left(65x-117\right)}{3}}{52}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

\mathrm{Join}\:117x+\frac{4\left(65x-117\right)}{3}:\quad \frac{611x-468}{3}

\frac{\frac{611x-468}{3}}{52}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

\frac{611x-468}{3\cdot \:52}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:52=156

\frac{611x-468}{156}

\mathrm{Factor}\:611x-468:\quad 13\left(47x-36\right)

\frac{13\left(47x-36\right)}{156}

\mathrm{Cancel\:the\:common\:factor:}\:13

\frac{47x-36}{12}

Therefore, 2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}

Keywords: algebraic expression , simplification

Learn more about algebraic expression from brainly.com/question/11336599

#learnwithBrainly

7 0
4 years ago
Help with math please!!!
saveliy_v [14]

Answer:

\Huge\boxed{240ft^2}

Step-by-step explanation:

Hello There!

The figure shown is a trapezoid with the following dimensions

base 1 = 12ft

base 2 = 20 ft

height = 15 ft

Given these dimensions we need to find the area

We can do this by using the area of a trapezoid formula

A=\frac{a+b}{2} h

where a and b = bases and h = height

Knowing the dimensions all we have to do is plug in the values

A=\frac{12+20}{2} 15\\12+20=32\\\frac{32}{2} =16\\16*15=240\\A=240ft^2

So we can conclude that the area of the floor that needs to be replaced with tile is 240 ft²

8 0
3 years ago
Read 2 more answers
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