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3 years ago

7x+3y=22 4y=20 I need to know how to write this equation out with the answer

Mathematics

2 answers:

xeze [42]3 years ago

5 0

7x+3y=22
4y=20

4y=20
y=5

Substitute to first equation
7x+15=22
7x=7
x=1

WITCHER [35]3 years ago

3 0

$\begin{cases} 7x+3y=22 \\ 4y=20 \ \ /:4 \end{cases}\\ \\\begin{cases} 7x+3 \cdot 5=22 \\ y= 5 \end{cases}\\ \\\begin{cases} 7x+15=22 \ \ |-15 \\ 4y=20 \end{cases}$

$\begin{cases} 7x+15 -15=22 -15 \\ y=5 \end{cases}\\ \\\begin{cases} 7x =7\ \ / :7 \\ y=5 \end{cases}\\ \\\begin{cases} x =1 \\ y=5 \end{cases}\\ \\$

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Ivenika [448]

Answer:

The points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

Step-by-step explanation:

The equation of the line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

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$\Rightarrow y=1.5x+5\cdots(i)$

For the point (4,11), pout x=4 in equation (i), we have

$y=1.5\times4 +5=11$ , which is given y coordinate, hence this point (4,11) lies on the line.

For the point (5,10), pout x=5 in equation (i), we have

$y=1.5\times5 +5=12.5,$ which is not the given y coordinate, hence the point (5,10) doesn't lie on the line.

For the point (6,14), pout x=6 in equation (i), we have

$y=1.5\times6 +5=14$ , which is the given y coordinate, hence the point (6,14) lies on the line.

For the point (30,50), pout x=30 in equation (i), we have

$y=1.5\times30 +5=50$ , which is the given y coordinate, hence the point (30,50) lies on the line.

For the point (40,60), pout x=40 in equation (i), we have

$y=1.5\times40 +5=65$ , which is not the given y coordinate, hence the point (40,60) doesn't lie on the line.

Hence, the points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

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